It is currently 16 Jun 2019, 23:45

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

GRE Math Challenge #69- Quantity A: p^4 – p^6

Author Message
TAGS:
GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4810
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 117

Kudos [?]: 1895 [1] , given: 397

GRE Math Challenge #69- Quantity A: p^4 – p^6 [#permalink]  03 May 2015, 00:59
1
KUDOS
Expert's post
00:00

Question Stats:

52% (00:39) correct 48% (01:18) wrong based on 25 sessions
$$0 < p <1$$

Quantity A: $$p^4$$ – $$p^6$$
Quantity B: $$p^3$$– $$p^5$$

• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
[Reveal] Spoiler: OA

_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

GRE Instructor
Joined: 10 Apr 2015
Posts: 1962
Followers: 60

Kudos [?]: 1792 [1] , given: 9

Re: GRE Math Challenge #69 [#permalink]  18 May 2015, 11:32
1
KUDOS
Expert's post
sandy wrote:
$$0 < p < 1$$

Quantity A: $$p^4$$ – $$p^6$$
Quantity B: $$p^3$$– $$p^5$$

Given: 0 < p < 1

If we factor each quantity, something nice happens:
Quantity A: p^4(1 – p^2)
Quantity B: p^3(1 – p^2)

NOTE: If 0 < p < 1, then p^2 is LESS THAN 1, which means 1 - p^2 must be POSITIVE.
As such, we can divide both quantities by (1 - p^2) to get:
Quantity A: p^4
Quantity B: p^3

NOTE: If 0 < p < 1, then p^3 is POSITIVE.
As such, we can divide both quantities by p^3 to get:
Quantity A: p
Quantity B: 1

Since 0 < p < 1, we can see that quantity B must be greater.
[Reveal] Spoiler:
B

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com

Intern
Joined: 26 Dec 2016
Posts: 4
Followers: 0

Kudos [?]: 7 [2] , given: 0

Re: GRE Math Challenge #69- Quantity A: p^4 – p^6 [#permalink]  22 Jan 2017, 21:57
2
KUDOS
A: P^4 - P^6
B: P^3 - P^5
Expand---
A: P^3 ( P^1 - P^3)
B: P^3 (1 - P^2)
Divide both by P^3
A: P^1 - P^3
B: 1 - P^2
Now, Expand A
A: P (1 - P^2)
B: 1 - P^2
Divide Both by (1 - P^2)
A: P
B: 1
Since P is Always less than 1, Answer is B
Re: GRE Math Challenge #69- Quantity A: p^4 – p^6   [#permalink] 22 Jan 2017, 21:57
Display posts from previous: Sort by