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# GRE Math Challenge #52- Quantity A: (250)(492)

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GRE Math Challenge #52- Quantity A: (250)(492) [#permalink]  03 May 2015, 00:34
Expert's post
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Question Stats:

76% (00:27) correct 23% (00:33) wrong based on 165 sessions
 Quantity A Quantity B $$(250)(492)$$ $$\frac{492,000}{4}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Sandy
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Re: GRE Math Challenge #52 [#permalink]  18 May 2015, 14:42
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Expert's post
sandy wrote:
Quantity A: (250)(492)
Quantity B: 492,000/4

No need to activate that clunky onscreen GRE calculator!!

Notice that 250 = 1000/4
So, let's take quantity A and replace 250 with 1000/4.
We get:
Quantity A:
(250)(492) = (1000/4)(492)
= 492,000/4

PERFECT! Compare with quantity B
Quantity B: 492,000/4

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com

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Re: GRE Math Challenge #52 [#permalink]  11 Aug 2019, 12:53
GreenlightTestPrep wrote:
sandy wrote:
Quantity A: (250)(492)
Quantity B: 492,000/4

No need to activate that clunky onscreen GRE calculator!!

Notice that 250 = 1000/4
So, let's take quantity A and replace 250 with 1000/4.
We get:
Quantity A:
(250)(492) = (1000/4)(492)
= 492,000/4

PERFECT! Compare with quantity B
Quantity B: 492,000/4

Cheers,
Brent

Hi Brent,

I don't follow your explanation. Can you explain it a different way maybe? I am unsure as to why we're noticing that 250=1000/4 and replacing.
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Re: GRE Math Challenge #52 [#permalink]  12 Aug 2019, 10:19
1
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Expert's post
JNeen wrote:

Hi Brent,

I don't follow your explanation. Can you explain it a different way maybe? I am unsure as to why we're noticing that 250=1000/4 and replacing.

Hi JNeen,

The two quantities are initially hard to compare because one quantity is in the form of a fraction with denominator 4 (Quantity B: 492,000/4) and the other quantity is not in the form of a fraction.

So, to make the comparison easier, I thought I might convert Quantity into a fraction with denominator 4.

So, I used the fact that we can rewrite 250 as a fraction with denominator 4.

We get:
Quantity A: $$(250)(492)=(\frac{1000}{4})(492)=(\frac{1000}{4})(\frac{492}{1}) = \frac{492,000}{4}$$

Quantity B: $$\frac{492,000}{4}$$

Does that help?

Cheers,
Brent
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Re: GRE Math Challenge #52- Quantity A: (250)(492) [#permalink]  15 Aug 2019, 14:31
1
KUDOS
For A, 492*250
For B, 492,000=492*1000/4=492*250
So ans is C
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Re: GRE Math Challenge #52- Quantity A: (250)(492) [#permalink]  15 Aug 2019, 23:20
First step is to look for common factors in both the quantities.
Since 492 is common, divide both the quantities by 492
You will get 250 on one side and 1000/4 on the other side
we know that 100/4 is 25. Therefore 1000/4 is 250
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Re: GRE Math Challenge #52 [#permalink]  16 Aug 2019, 12:14
GreenlightTestPrep wrote:
JNeen wrote:

Hi Brent,

I don't follow your explanation. Can you explain it a different way maybe? I am unsure as to why we're noticing that 250=1000/4 and replacing.

Hi JNeen,

The two quantities are initially hard to compare because one quantity is in the form of a fraction with denominator 4 (Quantity B: 492,000/4) and the other quantity is not in the form of a fraction.

So, to make the comparison easier, I thought I might convert Quantity into a fraction with denominator 4.

So, I used the fact that we can rewrite 250 as a fraction with denominator 4.

We get:
Quantity A: $$(250)(492)=(\frac{1000}{4})(492)=(\frac{1000}{4})(\frac{492}{1}) = \frac{492,000}{4}$$

Quantity B: $$\frac{492,000}{4}$$

Does that help?

Cheers,
Brent

Definitely does. Thank you!
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Re: GRE Math Challenge #52- Quantity A: (250)(492) [#permalink]  25 Aug 2019, 08:26
c
Re: GRE Math Challenge #52- Quantity A: (250)(492)   [#permalink] 25 Aug 2019, 08:26
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