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GRE Math Challenge #52 Quantity A: (250)(492) [#permalink]
03 May 2015, 00:34
Question Stats:
76% (00:27) correct
23% (00:33) wrong based on 165 sessions
Quantity A 
Quantity B 
\((250)(492)\) 
\(\frac{492,000}{4}\) 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
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Re: GRE Math Challenge #52 [#permalink]
18 May 2015, 14:42
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sandy wrote: Quantity A: (250)(492) Quantity B: 492,000/4
No need to activate that clunky onscreen GRE calculator!! Notice that 250 = 1000/4So, let's take quantity A and replace 250 with 1000/4. We get: Quantity A: (250)(492) = ( 1000/4)(492) = 492,000/4 PERFECT! Compare with quantity B Quantity B: 492,000/4 Answer: C Cheers, Brent
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Re: GRE Math Challenge #52 [#permalink]
11 Aug 2019, 12:53
GreenlightTestPrep wrote: sandy wrote: Quantity A: (250)(492) Quantity B: 492,000/4
No need to activate that clunky onscreen GRE calculator!! Notice that 250 = 1000/4So, let's take quantity A and replace 250 with 1000/4. We get: Quantity A: (250)(492) = ( 1000/4)(492) = 492,000/4 PERFECT! Compare with quantity B Quantity B: 492,000/4 Answer: C Cheers, Brent Hi Brent, I don't follow your explanation. Can you explain it a different way maybe? I am unsure as to why we're noticing that 250=1000/4 and replacing.



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Re: GRE Math Challenge #52 [#permalink]
12 Aug 2019, 10:19
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JNeen wrote: Hi Brent,
I don't follow your explanation. Can you explain it a different way maybe? I am unsure as to why we're noticing that 250=1000/4 and replacing.
Hi JNeen, The two quantities are initially hard to compare because one quantity is in the form of a fraction with denominator 4 (Quantity B: 492,000/4) and the other quantity is not in the form of a fraction. So, to make the comparison easier, I thought I might convert Quantity into a fraction with denominator 4. So, I used the fact that we can rewrite 250 as a fraction with denominator 4. We get: Quantity A: \((250)(492)=(\frac{1000}{4})(492)=(\frac{1000}{4})(\frac{492}{1}) = \frac{492,000}{4}\) Quantity B: \(\frac{492,000}{4}\) Answer: C Does that help? Cheers, Brent
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Re: GRE Math Challenge #52 Quantity A: (250)(492) [#permalink]
15 Aug 2019, 14:31
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For A, 492*250 For B, 492,000=492*1000/4=492*250 So ans is C



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Re: GRE Math Challenge #52 Quantity A: (250)(492) [#permalink]
15 Aug 2019, 23:20
First step is to look for common factors in both the quantities. Since 492 is common, divide both the quantities by 492 You will get 250 on one side and 1000/4 on the other side we know that 100/4 is 25. Therefore 1000/4 is 250 The answer is C



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Re: GRE Math Challenge #52 [#permalink]
16 Aug 2019, 12:14
GreenlightTestPrep wrote: JNeen wrote: Hi Brent,
I don't follow your explanation. Can you explain it a different way maybe? I am unsure as to why we're noticing that 250=1000/4 and replacing.
Hi JNeen, The two quantities are initially hard to compare because one quantity is in the form of a fraction with denominator 4 (Quantity B: 492,000/4) and the other quantity is not in the form of a fraction. So, to make the comparison easier, I thought I might convert Quantity into a fraction with denominator 4. So, I used the fact that we can rewrite 250 as a fraction with denominator 4. We get: Quantity A: \((250)(492)=(\frac{1000}{4})(492)=(\frac{1000}{4})(\frac{492}{1}) = \frac{492,000}{4}\) Quantity B: \(\frac{492,000}{4}\) Answer: C Does that help? Cheers, Brent Definitely does. Thank you!



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Re: GRE Math Challenge #52 Quantity A: (250)(492) [#permalink]
25 Aug 2019, 08:26
c




Re: GRE Math Challenge #52 Quantity A: (250)(492)
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25 Aug 2019, 08:26





