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GRE Math Challenge #32-x years old y years from now

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GRE Math Challenge #32-x years old y years from now [#permalink] New post 07 Sep 2014, 06:48
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Question Stats:

20% (00:39) correct 79% (00:46) wrong based on 29 sessions
Yann will be x years old y years from now. How old was z years ago?

A. x + y + z
B. x + y + z
C. x – y –z
D. y – x –z
E. z - y –x
[Reveal] Spoiler: OA

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Re: GRE Math Challenge #32-x years old y years from now [#permalink] New post 16 Jan 2018, 00:58
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E is the answer
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Re: GRE Math Challenge #32-x years old y years from now [#permalink] New post 16 Jan 2018, 10:31
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Its x-y-z
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Re: GRE Math Challenge #32-x years old y years from now [#permalink] New post 17 Jan 2018, 20:59
How is it E? I got C, by this -

Y = Yann's age now.
After y years, Yann is x => Y + y = x
z years ago, Yann's age was Y - z.

Y + y = x
Y = x - y
=> Y - z = x - y - z
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Re: GRE Math Challenge #32-x years old y years from now [#permalink] New post 04 Feb 2018, 11:35
I got C, whats the answer?

C=current age

X = age Y years from now

X = C + Y
C= X-Y
C-Z=age z years ago=X-Y-Z
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Re: GRE Math Challenge #32-x years old y years from now [#permalink] New post 10 Mar 2018, 23:30
the answer is C. let yann's current age be a, then his age y years from now will be x, i.e., x=a+y or a=x-y. His age z years ago was a-z, substitute value of a in 2nd expression, z years ago his age was --> x-y-z
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Re: GRE Math Challenge #32-x years old y years from now [#permalink] New post 14 Mar 2018, 00:38
The question is difficult to follow.
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Re: GRE Math Challenge #32-x years old y years from now [#permalink] New post 22 Mar 2018, 02:46
It's not difficult, but the trick in this questions is this: find the NOW!
Now+y=x, so Now=x-y
And z years ago will be x-y-z :D
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Re: GRE Math Challenge #32-x years old y years from now [#permalink] New post 05 Jul 2018, 19:46
sandy wrote:
Yann will be x years old y years from now. How old was z years ago?

A. x + y + z
B. x + y + z
C. x – y –z
D. y – x –z
E. z - y –x


Hi Sandy, kindly assist to review this. The answer should be C and not E. If it is indeed E, provide a solution that illustrates this. Thanks
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Re: GRE Math Challenge #32-x years old y years from now [#permalink] New post 05 Jul 2018, 22:52
Emike56 wrote:
sandy wrote:
Yann will be x years old y years from now. How old was z years ago?

A. x + y + z
B. x + y + z
C. x – y –z
D. y – x –z
E. z - y –x


Hi Sandy, kindly assist to review this. The answer should be C and not E. If it is indeed E, provide a solution that illustrates this. Thanks


Hi @Emike56,

Yes, (C) is the right answer.

@sandy

Please change the OA.

Thanks.
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Re: GRE Math Challenge #32-x years old y years from now [#permalink] New post 06 Jul 2018, 14:39
Expert's post
I think the answer should be C too. The explanations given before seems accurate.
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Re: GRE Math Challenge #32-x years old y years from now   [#permalink] 06 Jul 2018, 14:39
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