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GRE Math Challenge #30-In the history class that consisted

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GRE Math Challenge #30-In the history class that consisted [#permalink] New post 19 Sep 2014, 02:56
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Question Stats:

52% (00:54) correct 47% (00:57) wrong based on 23 sessions
In the history class that consisted of 30 students, the number of seniors was 3 more than twice the number of juniors, and 3/10 of the students were neither juniors nor seniors.

Quantity A
Quantity B
The number of juniors in the class
6




A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Last edited by Carcass on 14 Mar 2018, 15:32, edited 1 time in total.
Edited by Carcass
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Re: GRE Math Challenge #30-In the history class that consisted [#permalink] New post 20 Feb 2018, 14:35
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sandy wrote:
In the history class that consisted of 30 students, the number of seniors was 3 more than twice the number of juniors, and 3/10 of the students were neither juniors nor seniors

Column A: The number of juniors in the class
Column B: 6

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Let J = number of juniors in the class
Let S = number of seniors in the class


3/10 of the 30 students were neither juniors nor seniors
So, 7/10 were either juniors or seniors
7/10 of 30 = 21.
We can write: J + S = 21

...the number of seniors was 3 more than twice the number of juniors
We can write: S = 2J + 3

We now have the following system of equations:
J + S = 21
S = 2J + 3

Take the top equation and replace S with 2J + 3 to get; J + (2J + 3) = 21
Simplify: 3J + 3 = 21
Solve: J = 6

So, we get:
Quantity A: 6
Quantity B: 6

Answer: C

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Brent
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Re: GRE Math Challenge #30-In the history class that consisted [#permalink] New post 24 Feb 2018, 18:10
c
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Re: GRE Math Challenge #30-In the history class that consisted [#permalink] New post 28 Feb 2018, 13:09
provide source please
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Re: GRE Math Challenge #30-In the history class that consisted [#permalink] New post 28 Feb 2018, 13:14
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Re: GRE Math Challenge #30-In the history class that consisted [#permalink] New post 14 Mar 2018, 15:21
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correct: C
Total_number_of_students: 30
seniors = 3 + 2* juniors
not_junior_and_not_senior = 3/10 * total_number_of_students = 3/10 * 30 = 9 so 30 - 9 = 21 students are seniors or juniors:
21 = seniors + juniors =3 + 2* juniors + juniors = 3 + 3*juniors -> juniors = 6
So there are 6 juniors in the history class. and A and B are equal.
Re: GRE Math Challenge #30-In the history class that consisted   [#permalink] 14 Mar 2018, 15:21
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GRE Math Challenge #30-In the history class that consisted

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