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GRE Math Challenge #25- The arithmetic mean of w,x and y is

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GRE Math Challenge #25- The arithmetic mean of w,x and y is [#permalink] New post 18 Sep 2014, 12:00
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Question Stats:

65% (00:59) correct 34% (00:56) wrong based on 145 sessions
The arithmetic mean of w,x and y is 9


Quantity A
Quantity B
The average of 2w-y, 3x+6 and 3y-x
20




A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Last edited by Carcass on 17 Feb 2020, 11:12, edited 1 time in total.
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Re: GRE Math Challenge #25 [#permalink] New post 18 May 2015, 17:07
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sandy wrote:
The arithmetic mean of w,x and y is 9

Column A: The average of 2w-y, 3x+6 and 3y-x
Column B: 20


Given: The arithmetic mean of w, x and y is 9
This means that (w + x + y)/3 = 9
Multiply both sides of the equation by 3 to get: w + x + y = 27


Column A: The average of 2w-y, 3x+6 and 3y-x
Average of these 3 values = [(2w-y) + (3x+6) + (3y-x)]/3
Simplify numerator to get: [2w + 2x + 2y + 6]/3
Factor the numerator to get: [2(w + x + y + 3]/3

KEY STEP: Replace w + x + y with 27 [from earlier conclusion with given information]
We get: [2(27 + 3]/3
Simplify: 60/3 = 20

Column B: 20

Answer:
[Reveal] Spoiler:
C


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Brent
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Re: GRE Math Challenge #25- The arithmetic mean of w,x and y is [#permalink] New post 17 Feb 2020, 11:13
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Re: GRE Math Challenge #25- The arithmetic mean of w,x and y is   [#permalink] 17 Feb 2020, 11:13
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GRE Math Challenge #25- The arithmetic mean of w,x and y is

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