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GRE Math Challenge #14-at a certain school the ratio of boys

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GRE Math Challenge #14-at a certain school the ratio of boys [#permalink] New post 02 Sep 2014, 02:08
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Question Stats:

52% (00:21) correct 48% (01:08) wrong based on 25 sessions
Yesterday, at a certain school, the ratio of boys to girls was 1 to 3. Today, an equal number of boys and girls joined the school. The number that joined was greater than zero and no students left.


Quantity A
Quantity B
Ratio of boys to girls now
\(\frac{1}{3}\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: GRE Math Challenge #14-at a certain school the ratio of boys [#permalink] New post 16 Jan 2018, 17:41
A is greater, i try plug the number in,
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Re: GRE Math Challenge #14-at a certain school the ratio of boys [#permalink] New post 18 Jan 2018, 00:08
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please explain why the answer is A

Suppose there is 1 boy and 3 girls at school
and same number of boys and girls are added the new ratio of B/G would be 2/6 = 1/3

Suppose there are 4 boys and 12 girls at school
and same number of boys and girls are added the new ratio of B/G would be 8/24 = 1/3
(c)
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Re: GRE Math Challenge #14-at a certain school the ratio of boys [#permalink] New post 18 Jan 2018, 08:25
If equal number of students joined then the ratio remains the same thus, Both quantities are equal
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Re: GRE Math Challenge #14-at a certain school the ratio of boys [#permalink] New post 18 Jan 2018, 15:45
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Couple of things happening here.

First is you have a implied integer restriction. You can't have half a person right? The second portion says both boys and girls are equal. If you add the smallest possible increase to both (1) then it becomes \(\frac{1}{2}\) which is greater that 1/3.

Any integer you add to both the top and bottom of the fraction will increase it therefore A.
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Re: GRE Math Challenge #14-at a certain school the ratio of boys [#permalink] New post 18 Jan 2018, 20:18
Thank You
I got fooled by the wording of the question
"Today, an equal number of boys and girls joined the school"
I interpreted it as the number of boys and girls equal to the ratio
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Re: GRE Math Challenge #14-at a certain school the ratio of boys [#permalink] New post 18 Jan 2018, 22:47
Quantity A is Larger
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Re: GRE Math Challenge #14-at a certain school the ratio of boys [#permalink] New post 19 Jan 2018, 01:05
SherpaPrep wrote:
Couple of things happening here.

First is you have a implied integer restriction. You can't have half a person right? The second portion says both boys and girls are equal. If you add the smallest possible increase to both (1) then it becomes \(\frac{1}{2}\) which is greater that 1/3.

Any integer you add to both the top and bottom of the fraction will increase it therefore A.




Oh Okay, understood now. I did not really took note of the equal number of boys and girls added.

Thank you.
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Re: GRE Math Challenge #14-at a certain school the ratio of boys [#permalink] New post 26 Jan 2018, 10:00
SherpaPrep wrote:
Couple of things happening here.

First is you have a implied integer restriction. You can't have half a person right? The second portion says both boys and girls are equal. If you add the smallest possible increase to both (1) then it becomes \(\frac{1}{2}\) which is greater that 1/3.

Any integer you add to both the top and bottom of the fraction will increase it therefore A.


thank you!... I understand now, I thought that the number of girls and boys joined the school were equal to the ones were already there.
Re: GRE Math Challenge #14-at a certain school the ratio of boys   [#permalink] 26 Jan 2018, 10:00
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GRE Math Challenge #14-at a certain school the ratio of boys

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