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# GRE Math Challenge #14 - 72.42= k(24 + n/100)

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Joined: 07 Jun 2014
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GRE 1: Q167 V156
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GRE Math Challenge #14 - 72.42= k(24 + n/100) [#permalink]  09 Sep 2014, 01:37
Expert's post
00:00

Question Stats:

71% (01:18) correct 28% (03:15) wrong based on 7 sessions
If 0 < n < 100 and 72.42 = k(24 + n/100), then k + n =

[Reveal] Spoiler: Answer
17

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Sandy
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Re: GRE Math Challenge #14 - 72.42= k(24 + n/100) [#permalink]  22 Feb 2018, 10:33
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sandy wrote:
If 0 < n < 100 and 72.42 = k(24 + n/100), then k + n =

[Reveal] Spoiler: Answer
17

Given: 72.42 = k(24 + n/100)
Expand right side to get: 72.42 = 24k + kn/100

We already know that 72.42 = 72 + 42/100

So, we conclude that 72 = 24k
And kn = 42

If 72 = 24k, then k = 3
Now take the second equation, and replace k with 3 to get: 3n = 42
This means n = 14

So, k + n = 3 + 14 = 17

Answer: 17

Cheers,
Brent
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Re: GRE Math Challenge #14 - 72.42= k(24 + n/100) [#permalink]  23 Feb 2018, 01:42
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if $$K = 100$$ and $$n = - 2327.58$$

This satisfies the eqn and condition and their sum is $$-2227.58$$
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GRE Instructor
Joined: 10 Apr 2015
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Kudos [?]: 1135 [1] , given: 7

Re: GRE Math Challenge #14 - 72.42= k(24 + n/100) [#permalink]  23 Feb 2018, 08:46
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Expert's post
amorphous wrote:
if $$K = 100$$ and $$n = - 2327.58$$

This satisfies the eqn and condition and their sum is $$-2227.58$$

Good point!
I have added a restriction to n to prevent more than 1 correct answer.

Cheers,
Brent
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Re: GRE Math Challenge #14 - 72.42= k(24 + n/100)   [#permalink] 23 Feb 2018, 08:46
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# GRE Math Challenge #14 - 72.42= k(24 + n/100)

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