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GRE Math Challenge #128- 100x<y 1000x < 2y

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GRE Math Challenge #128- 100x<y 1000x < 2y [#permalink] New post 15 May 2015, 11:32
Expert's post
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Question Stats:

62% (01:10) correct 37% (02:03) wrong based on 27 sessions
100x < y
1000x < 2y

Quantity A: 1100x
Quantity B: y

• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
[Reveal] Spoiler: OA

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Re: GRE Math Challenge #128 [#permalink] New post 17 May 2015, 08:34
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Expert's post
sandy wrote:
100x<y
1000x < 2y

Quantity A: 1100x
Quantity B: y


One of my favorite Quantitative Comparison strategies is called "Looking for Equality" (free video on this topic here: http://www.greenlighttestprep.com/modul ... on?id=1099).
In this strategy, I first look for values of x and y that make the two quantities are equal. This often involves checking some easy numbers like 0, 1, -1 etc.

Consider these two cases:
Case #1: x = 1 and y = 1100
Notice that these values satisfy the given conditions that 100 x < y and 1000x < 2y
Now check the quantities:
Quantity A: 1100x = (1100)(1) = 1100
Quantity B: y = 1100
Since the two quantities are EQUAL, the correct answer is EITHER C or D

Now try some other values of x and y:
Case #2: x = 1 and y = 1200
Notice that these values satisfy the given conditions that 100 x < y and 1000x < 2y
Now check the quantities:
Quantity A: 1100x = (1100)(1) = 1100
Quantity B: y = 1200
Since the two quantities are NOT EQUAL, the correct answer is
[Reveal] Spoiler:
D


Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
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Re: GRE Math Challenge #128- 100x<y 1000x < 2y [#permalink] New post 11 Feb 2017, 15:46
Are there alternative ways to solve this question?
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Re: GRE Math Challenge #128- 100x<y 1000x < 2y [#permalink] New post 11 May 2017, 10:06
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add two inequalities
1100x<3y

let y=1
1100x < 3

1100x can be 2,1,0,-1,......

correct choice:D
Re: GRE Math Challenge #128- 100x<y 1000x < 2y   [#permalink] 11 May 2017, 10:06
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