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GRE Math Challenge #122- In a certain city, 20ºF was

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GRE Math Challenge #122- In a certain city, 20ºF was [#permalink] New post 15 May 2015, 11:26
Expert's post
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Question Stats:

71% (00:38) correct 28% (00:12) wrong based on 14 sessions
In a certain city, 20ºF was the average (arithmetic mean) of the low temperatures of xºF, 25ºF, and 37ºF on three consecutive days.

Quantity A: x
Quantity B: 0

• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
[Reveal] Spoiler: OA

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Re: GRE Math Challenge #122 [#permalink] New post 18 May 2015, 11:06
Expert's post
sandy Array[WROTE]:
In a certain city, 20ºF was the average (arithmetic mean) of the low temperatures of xºF, 25ºF, and 37ºF on three consecutive days.

Quantity A: x
Quantity B: 0


If the mean of the THREE values is 20 degrees, then we can write: (x + 25 + 37)/3 = 20
To solve for x, first multiply both sides of the equation by 3 to get: x + 25 + 37 = 60
Simplify: x + 62 = 60
Solve: x = -2

So, we get:
Quantity A: -2
Quantity B: 0

Answer:
[Reveal] Spoiler:
B


Cheers,
Brent
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Re: GRE Math Challenge #122   [#permalink] 18 May 2015, 11:06
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GRE Math Challenge #122- In a certain city, 20ºF was

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