Author 
Message 
TAGS:


GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
WE: Business Development (Energy and Utilities)
Followers: 105
Kudos [?]:
1783
[2]
, given: 397

GRE Math Challenge #120x < y < z [#permalink]
15 May 2015, 11:23
2
This post received KUDOS
Question Stats:
56% (00:37) correct
43% (00:45) wrong based on 32 sessions
\(x < y < z\)
Quantity A 
Quantity B 
\(\frac{(x+y+z)}{3}\) 
\(z\) 
• Quantity A is greater. • Quantity B is greater. • Both Quantities are Equal • Cannot be determined
_________________
Sandy If you found this post useful, please let me know by pressing the Kudos Button
Try our free Online GRE Test
Last edited by Carcass on 11 Aug 2018, 22:49, edited 1 time in total.
Edited by Carcass




GRE Instructor
Joined: 10 Apr 2015
Posts: 1543
Followers: 56
Kudos [?]:
1466
[1]
, given: 8

Re: GRE Math Challenge #120 [#permalink]
17 May 2015, 09:26
1
This post received KUDOS
sandy wrote: \(x < y < z\)
Quantity A: (x+y+z)/3 Quantity B: z
Nice question! IMPORTANT: Notice that (x+y+z)/3 is equal to the AVERAGE of x, y and z. Since x < y < z, the average of these 3 values must be greater than x and less than z. Since the average of the 3 values must be less than z, we can conclude that (x+y+z)/3 is definitely less than zAnswer: Cheers, Brent
_________________
Brent Hanneson – Creator of greenlighttestprep.com Sign up for our free GRE Question of the Day emails



Manager
Joined: 06 Jun 2018
Posts: 94
Followers: 0
Kudos [?]:
58
[1]
, given: 0

Re: GRE Math Challenge #120x < y < z [#permalink]
11 Aug 2018, 11:51
1
This post received KUDOS
sandy wrote: \(x < y < z\)
Quantity A: (x+y+z)/3 Quantity B: z
• Quantity A is greater. • Quantity B is greater. • Both Quantities are Equal • Cannot be determined x<y<z. we don't know whether they are consecutive or not. Even if they are consecutive average will always be lower than the highest numbers. So, z is greater. The best answer is B.



Intern
Joined: 03 Aug 2018
Posts: 4
Followers: 0
Kudos [?]:
0
[0], given: 1

Re: GRE Math Challenge #120x < y < z [#permalink]
13 Aug 2018, 16:52
sandy wrote: \(x < y < z\)
Quantity A 
Quantity B 
\(\frac{(x+y+z)}{3}\) 
\(z\) 
• Quantity A is greater. • Quantity B is greater. • Both Quantities are Equal • Cannot be determined Hi Guys, I don´t know if I am missing something on the statement of the question. I understand the reasoning mentioned regarding the average, nonetheless, if we pick the numbers: 1<1<9 wouldn't the answer be D since (1+1+9)/3 = 3 which is the same as z Cheers and thanks for any explanation I am missing



GRE Instructor
Joined: 10 Apr 2015
Posts: 1543
Followers: 56
Kudos [?]:
1466
[2]
, given: 8

Re: GRE Math Challenge #120x < y < z [#permalink]
13 Aug 2018, 19:12
2
This post received KUDOS
josemu wrote: sandy wrote: \(x < y < z\)
Quantity A 
Quantity B 
\(\frac{(x+y+z)}{3}\) 
\(z\) 
• Quantity A is greater. • Quantity B is greater. • Both Quantities are Equal • Cannot be determined Hi Guys, I don´t know if I am missing something on the statement of the question. I understand the reasoning mentioned regarding the average, nonetheless, if we pick the numbers: 1<1<9 wouldn't the answer be D since (1+1+9)/3 = 3 which is the same as zCheers and thanks for any explanation I am missing Be careful. In your example, z = 9, and quantity A = 3 Cheers, Brent
_________________
Brent Hanneson – Creator of greenlighttestprep.com Sign up for our free GRE Question of the Day emails



Intern
Joined: 03 Aug 2018
Posts: 4
Followers: 0
Kudos [?]:
0
[0], given: 1

Re: GRE Math Challenge #120x < y < z [#permalink]
13 Aug 2018, 19:36
GreenlightTestPrep wrote: josemu wrote: sandy wrote: \(x < y < z\)
Quantity A 
Quantity B 
\(\frac{(x+y+z)}{3}\) 
\(z\) 
• Quantity A is greater. • Quantity B is greater. • Both Quantities are Equal • Cannot be determined Hi Guys, I don´t know if I am missing something on the statement of the question. I understand the reasoning mentioned regarding the average, nonetheless, if we pick the numbers: 1<1<9 wouldn't the answer be D since (1+1+9)/3 = 3 which is the same as zCheers and thanks for any explanation I am missing Be careful. In your example, z = 9, and quantity A = 3 Cheers, Brent Hi Brent, You are absolutely right and now that I am coming back at it, everything makes sense (about the average rule). It is what happens when you try too much at something and forget sometimes the "obvious" and you can´t see past an idea. It is always good to take a step back and look at it. Thanks !



Intern
Joined: 13 Jul 2018
Posts: 33
GPA: 4
WE: Programming (Computer Software)
Followers: 0
Kudos [?]:
19
[0], given: 9

Re: GRE Math Challenge #120x < y < z [#permalink]
15 Aug 2018, 17:19
josemu wrote: sandy wrote: \(x < y < z\)
Quantity A 
Quantity B 
\(\frac{(x+y+z)}{3}\) 
\(z\) 
• Quantity A is greater. • Quantity B is greater. • Both Quantities are Equal • Cannot be determined Hi Guys, I don´t know if I am missing something on the statement of the question. I understand the reasoning mentioned regarding the average, nonetheless, if we pick the numbers: 1<1<9 wouldn't the answer be D since (1+1+9)/3 = 3 which is the same as z Cheers and thanks for any explanation I am missing In your example, the value of z is 9, while the average is 3.




Re: GRE Math Challenge #120x < y < z
[#permalink]
15 Aug 2018, 17:19





