It is currently 14 Dec 2018, 12:23
My Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

GRE Math Challenge #120-x < y < z

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
2 KUDOS received
GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1659 [2] , given: 396

CAT Tests
GRE Math Challenge #120-x < y < z [#permalink] New post 15 May 2015, 11:23
2
This post received
KUDOS
Expert's post
00:00

Question Stats:

68% (00:39) correct 32% (00:36) wrong based on 25 sessions
\(x < y < z\)

Quantity A
Quantity B
\(\frac{(x+y+z)}{3}\)
\(z\)



• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
[Reveal] Spoiler: OA

_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test


Last edited by Carcass on 11 Aug 2018, 22:49, edited 1 time in total.
Edited by Carcass
1 KUDOS received
GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 1242
Followers: 46

Kudos [?]: 1129 [1] , given: 7

Re: GRE Math Challenge #120 [#permalink] New post 17 May 2015, 09:26
1
This post received
KUDOS
Expert's post
sandy wrote:
\(x < y < z\)

Quantity A: (x+y+z)/3
Quantity B: z


Nice question!

IMPORTANT: Notice that (x+y+z)/3 is equal to the AVERAGE of x, y and z.
Since x < y < z, the average of these 3 values must be greater than x and less than z.
Since the average of the 3 values must be less than z, we can conclude that (x+y+z)/3 is definitely less than z

Answer:
[Reveal] Spoiler:
B


Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com
Image
Sign up for our free GRE Question of the Day emails

1 KUDOS received
Manager
Manager
Joined: 06 Jun 2018
Posts: 94
Followers: 0

Kudos [?]: 56 [1] , given: 0

Re: GRE Math Challenge #120-x < y < z [#permalink] New post 11 Aug 2018, 11:51
1
This post received
KUDOS
sandy wrote:
\(x < y < z\)

Quantity A: (x+y+z)/3
Quantity B: z

• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined



x<y<z. we don't know whether they are consecutive or not. Even if they are consecutive average will always be lower than the highest numbers. So, z is greater.

The best answer is B.
Intern
Intern
Joined: 03 Aug 2018
Posts: 4
Followers: 0

Kudos [?]: 0 [0], given: 1

Re: GRE Math Challenge #120-x < y < z [#permalink] New post 13 Aug 2018, 16:52
sandy wrote:
\(x < y < z\)

Quantity A
Quantity B
\(\frac{(x+y+z)}{3}\)
\(z\)



• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined


Hi Guys,

I don´t know if I am missing something on the statement of the question. I understand the reasoning mentioned regarding the average, nonetheless, if we pick the numbers: -1<1<9
wouldn't the answer be D since (-1+1+9)/3 = 3 which is the same as z

Cheers and thanks for any explanation I am missing
2 KUDOS received
GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 1242
Followers: 46

Kudos [?]: 1129 [2] , given: 7

Re: GRE Math Challenge #120-x < y < z [#permalink] New post 13 Aug 2018, 19:12
2
This post received
KUDOS
Expert's post
josemu wrote:
sandy wrote:
\(x < y < z\)

Quantity A
Quantity B
\(\frac{(x+y+z)}{3}\)
\(z\)



• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined


Hi Guys,

I don´t know if I am missing something on the statement of the question. I understand the reasoning mentioned regarding the average, nonetheless, if we pick the numbers: -1<1<9
wouldn't the answer be D since (-1+1+9)/3 = 3 which is the same as z

Cheers and thanks for any explanation I am missing


Be careful. In your example, z = 9, and quantity A = 3

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com
Image
Sign up for our free GRE Question of the Day emails

Intern
Intern
Joined: 03 Aug 2018
Posts: 4
Followers: 0

Kudos [?]: 0 [0], given: 1

Re: GRE Math Challenge #120-x < y < z [#permalink] New post 13 Aug 2018, 19:36
GreenlightTestPrep wrote:
josemu wrote:
sandy wrote:
\(x < y < z\)

Quantity A
Quantity B
\(\frac{(x+y+z)}{3}\)
\(z\)



• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined


Hi Guys,

I don´t know if I am missing something on the statement of the question. I understand the reasoning mentioned regarding the average, nonetheless, if we pick the numbers: -1<1<9
wouldn't the answer be D since (-1+1+9)/3 = 3 which is the same as z

Cheers and thanks for any explanation I am missing


Be careful. In your example, z = 9, and quantity A = 3

Cheers,
Brent


Hi Brent,

You are absolutely right and now that I am coming back at it, everything makes sense (about the average rule). It is what happens when you try too much at something and forget sometimes the "obvious" and you can´t see past an idea. It is always good to take a step back and look at it. Thanks !
Intern
Intern
Joined: 13 Jul 2018
Posts: 33
GRE 1: Q159 V151
GPA: 4
WE: Programming (Computer Software)
Followers: 0

Kudos [?]: 18 [0], given: 9

Reviews Badge
Re: GRE Math Challenge #120-x < y < z [#permalink] New post 15 Aug 2018, 17:19
josemu wrote:
sandy wrote:
\(x < y < z\)

Quantity A
Quantity B
\(\frac{(x+y+z)}{3}\)
\(z\)



• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined


Hi Guys,

I don´t know if I am missing something on the statement of the question. I understand the reasoning mentioned regarding the average, nonetheless, if we pick the numbers: -1<1<9
wouldn't the answer be D since (-1+1+9)/3 = 3 which is the same as z

Cheers and thanks for any explanation I am missing


In your example, the value of z is 9, while the average is 3.
Re: GRE Math Challenge #120-x < y < z   [#permalink] 15 Aug 2018, 17:19
Display posts from previous: Sort by

GRE Math Challenge #120-x < y < z

  Question banks Downloads My Bookmarks Reviews Important topics  


GRE Prep Club Forum Home| About| Terms and Conditions and Privacy Policy| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.