Author 
Message 
TAGS:


GMAT Club Legend
Joined: 07 Jun 2014
Posts: 4855
WE: Business Development (Energy and Utilities)
Followers: 98
Kudos [?]:
1715
[0], given: 397

GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
15 May 2015, 11:57
Question Stats:
87% (02:06) correct
12% (00:00) wrong based on 8 sessions
Attachment:
square.jpg [ 12.91 KiB  Viewed 702 times ]
In the figure above, ABCE is a square. What are the coordinates of point B? (A) (4,2) (B) (2,4) (C) (2,6) (D) (4, 6) (E) (6,2)
_________________
Sandy If you found this post useful, please let me know by pressing the Kudos Button
Try our free Online GRE Test




Director
Joined: 20 Apr 2016
Posts: 787
Followers: 7
Kudos [?]:
559
[0], given: 101

Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
19 Dec 2017, 10:55
sandy wrote: In the figure above, ABCE is a square. What are the coordinates of point B? (A) (4,2) (B) (2,4) (C) (2,6) (D) (4, 6) (E) (6,2) Here the distance between the two coordinates (6,0) and (0,4) is given by = \(\sqrt{{(60)^2 + (0+4)^2}}\) =\(\sqrt{52}\) Since the figure is a square all the distance between the each coordinates = \(\sqrt{52}\) Let the coordinate of B = (x,y) Now the distance between the coordinate (6, 0) and (x, y) = \(\sqrt{52}\) or \(\sqrt{{(x+6)^2 + (y0)^2}}\) = \(\sqrt{52}\) Now looking at the values only the above equation satisfy only when x= 2 and y= 6. Hence the coordinate of B is (2,6)
_________________
If you found this post useful, please let me know by pressing the Kudos Button



Manager
Joined: 27 Sep 2017
Posts: 112
Followers: 1
Kudos [?]:
29
[0], given: 4

Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
19 Dec 2017, 17:13
pranab01 wrote: sandy wrote: In the figure above, ABCE is a square. What are the coordinates of point B? (A) (4,2) (B) (2,4) (C) (2,6) (D) (4, 6) (E) (6,2) Here the distance between the two coordinates (6,0) and (0,4) is given by = \(\sqrt{{(60)^2 + (0+4)^2}}\) =\(\sqrt{52}\) Since the figure is a square all the distance between the each coordinates = \(\sqrt{52}\) Let the coordinate of B = (x,y) Now the distance between the coordinate (6, 0) and (x, y) = \(\sqrt{52}\) or \(\sqrt{{(x+6)^2 + (y0)^2}}\) = \(\sqrt{52}\) Now looking at the values only the above equation satisfy only when x= 2 and y= 6. Hence the coordinate of B is (2,6) Well I can NOT see the pic though



Intern
Joined: 16 Nov 2017
Posts: 1
Followers: 0
Kudos [?]:
0
[0], given: 0

Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
20 Dec 2017, 00:36
images are not loading. i have opened in chome and explorer but didnt work out



Director
Joined: 20 Apr 2016
Posts: 787
Followers: 7
Kudos [?]:
559
[0], given: 101

Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
20 Dec 2017, 20:02
Is the diagram visible? and also open up the "spoiler"
_________________
If you found this post useful, please let me know by pressing the Kudos Button



Intern
Joined: 21 Nov 2017
Posts: 33
Followers: 0
Kudos [?]:
10
[0], given: 0

Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
02 May 2018, 17:52
Let M be the center of square ABCD. Then, M is the midpoint of both AC and BD. We can find coordinates of M as follows: . M is midpoint of AC > x(M) = (6+4)/2; y(M) = (0+2)/2 or M(1,1) . M is midpoint of BD > x(B) = (2xM  xD) = 20 = 2; y(B) = (2yM  yD) = 2(4) = 6 Finally, we get B(2,6) > C



Intern
Joined: 27 Oct 2018
Posts: 49
Followers: 0
Kudos [?]:
12
[0], given: 27

Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
02 Nov 2018, 10:43
Checking options is the best way out



Senior Manager
Joined: 09 Nov 2018
Posts: 482
Followers: 0
Kudos [?]:
16
[0], given: 1

Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
08 Jan 2019, 19:37
By visualizing options and coordinates in diagram answer is C.



Senior Manager
Joined: 09 Nov 2018
Posts: 482
Followers: 0
Kudos [?]:
16
[0], given: 1

Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
08 Jan 2019, 19:50
grefox wrote: Let M be the center of square ABCD. Then, M is the midpoint of both AC and BD. We can find coordinates of M as follows: . M is midpoint of AC > x(M) = (6+4)/2; y(M) = (0+2)/2 or M(1,1) . M is midpoint of BD > x(B) = (2xM  xD) = 20 = 2; y(B) = (2yM  yD) = 2(4) = 6 Finally, we get B(2,6) > C Different view, and great.




Re: GRE Math Challenge#116In the figure above, ABCE is a square
[#permalink]
08 Jan 2019, 19:50





