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GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
15 May 2015, 11:57
Question Stats:
90% (01:46) correct
10% (00:00) wrong based on 10 sessions
Attachment:
square.jpg [ 12.91 KiB  Viewed 798 times ]
In the figure above, ABCE is a square. What are the coordinates of point B? (A) (4,2) (B) (2,4) (C) (2,6) (D) (4, 6) (E) (6,2)
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Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
19 Dec 2017, 10:55
sandy wrote: In the figure above, ABCE is a square. What are the coordinates of point B? (A) (4,2) (B) (2,4) (C) (2,6) (D) (4, 6) (E) (6,2) Here the distance between the two coordinates (6,0) and (0,4) is given by = \(\sqrt{{(60)^2 + (0+4)^2}}\) =\(\sqrt{52}\) Since the figure is a square all the distance between the each coordinates = \(\sqrt{52}\) Let the coordinate of B = (x,y) Now the distance between the coordinate (6, 0) and (x, y) = \(\sqrt{52}\) or \(\sqrt{{(x+6)^2 + (y0)^2}}\) = \(\sqrt{52}\) Now looking at the values only the above equation satisfy only when x= 2 and y= 6. Hence the coordinate of B is (2,6)
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Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
19 Dec 2017, 17:13
pranab01 wrote: sandy wrote: In the figure above, ABCE is a square. What are the coordinates of point B? (A) (4,2) (B) (2,4) (C) (2,6) (D) (4, 6) (E) (6,2) Here the distance between the two coordinates (6,0) and (0,4) is given by = \(\sqrt{{(60)^2 + (0+4)^2}}\) =\(\sqrt{52}\) Since the figure is a square all the distance between the each coordinates = \(\sqrt{52}\) Let the coordinate of B = (x,y) Now the distance between the coordinate (6, 0) and (x, y) = \(\sqrt{52}\) or \(\sqrt{{(x+6)^2 + (y0)^2}}\) = \(\sqrt{52}\) Now looking at the values only the above equation satisfy only when x= 2 and y= 6. Hence the coordinate of B is (2,6) Well I can NOT see the pic though



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Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
20 Dec 2017, 00:36
images are not loading. i have opened in chome and explorer but didnt work out



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Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
20 Dec 2017, 20:02
Is the diagram visible? and also open up the "spoiler"
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Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
02 May 2018, 17:52
Let M be the center of square ABCD. Then, M is the midpoint of both AC and BD. We can find coordinates of M as follows: . M is midpoint of AC > x(M) = (6+4)/2; y(M) = (0+2)/2 or M(1,1) . M is midpoint of BD > x(B) = (2xM  xD) = 20 = 2; y(B) = (2yM  yD) = 2(4) = 6 Finally, we get B(2,6) > C



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Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
02 Nov 2018, 10:43
Checking options is the best way out



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Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
08 Jan 2019, 19:37
By visualizing options and coordinates in diagram answer is C.



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Re: GRE Math Challenge#116In the figure above, ABCE is a square [#permalink]
08 Jan 2019, 19:50
grefox wrote: Let M be the center of square ABCD. Then, M is the midpoint of both AC and BD. We can find coordinates of M as follows: . M is midpoint of AC > x(M) = (6+4)/2; y(M) = (0+2)/2 or M(1,1) . M is midpoint of BD > x(B) = (2xM  xD) = 20 = 2; y(B) = (2yM  yD) = 2(4) = 6 Finally, we get B(2,6) > C Different view, and great.




Re: GRE Math Challenge#116In the figure above, ABCE is a square
[#permalink]
08 Jan 2019, 19:50





