sandy wrote:

\((n/4)+(r/8) = (s/8) + (t/6)\)

n, r, s, and t are positive integers.

Quantity A: 2n + r

Quantity B: 2s + t

Given:

(n/4)+(r/8) = (s/8) + (t/6) This equation has a lot of fractions. Let's first make things easier by eliminating the fractions.

The denominators are 4, 8, and 6.

The least common multiple of 4, 8 and 6 is 24, so let's multiply both both sides of the equation by 24 to get:

6n + 3r = 3s + 4tNOTICE that Quantity (2n + r) is SIMILAR to

6n + 3r, Let's use this fact!

Take

6n + 3r = 3s + 4t and divide both sides by 3 to get:

2n + r = s + (4/3)tNow replace Quantity A with

s + (4/3)t to get:

Quantity A:

s + (4/3)tQuantity B: 2s + t

Now subtract s from both quantities AND subtract t from both quantities to get:

Quantity A: (1/3)t

Quantity B: s

At this point, it's impossible to tell which quantity is greater.

So, the answer is D

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

Sign up for our free GRE Question of the Day emails