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GRE Math Challenge #109- The area of region OPQ or 10

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GRE Math Challenge #109- The area of region OPQ or 10 [#permalink] New post 09 May 2015, 11:28
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68% (01:07) correct 31% (01:33) wrong based on 58 sessions
Attachment:
#greprepclub PQ=OA=5.jpg
#greprepclub PQ=OA=5.jpg [ 21.25 KiB | Viewed 1288 times ]


\(PQ=OQ=5\)

Quantity A
Quantity B
The area of region \(OPQ\)
\(10\)



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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[Reveal] Spoiler: OA

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Re: GRE Math Challenge #109- The area of region OPQ or 10 [#permalink] New post 11 May 2018, 11:13
Greater if its a right angled triangle. In what case is it less than 10?? Can someone explain this??
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Re: GRE Math Challenge #109- The area of region OPQ or 10 [#permalink] New post 17 Dec 2019, 05:38
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Bump for further discussion
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Re: GRE Math Challenge #109- The area of region OPQ or 10 [#permalink] New post 17 Dec 2019, 20:33
Carcass wrote:
Bump for further discussion

It will be nice if we find the location of A in the figure.
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Re: GRE Math Challenge #109- The area of region OPQ or 10 [#permalink] New post 21 Dec 2019, 21:18
Ashgre wrote:
Carcass wrote:
Bump for further discussion

It will be nice if we find the location of A in the figure.



Hahahha right
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Re: GRE Math Challenge #109- The area of region OPQ or 10 [#permalink] New post 22 Dec 2019, 00:42
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Edited the original post by sandy.

Thank you to pointed out
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Re: GRE Math Challenge #109- The area of region OPQ or 10 [#permalink] New post 22 Dec 2019, 15:13
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Okay, this is an isosceles triangle, and the largest area will be when the third side is also 5, and that area will be 1/2*5*5*sqrt3, which is greater than ten. But picture the triangle squashed down so that the height is .001. The base is less than 10, so area will be less than 1/2*.001*10. So answer D.
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Re: GRE Math Challenge #109- The area of region OPQ or 10 [#permalink] New post 17 Aug 2020, 18:59
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Fact: given two sides of a triangle, the area is maximized when the triangle is a right triangle with the given two sides as legs.


Therefore the max area would be

(1/2)(5)(5)=25/2= 12.5

12.5>10
Choice A


Given the two sides the area of the triangle can be made arbitrarily small by increasing the angle of OQP more and more.
The height will be approaching zero, therefore the area becomes smaller and smaller with 0 as a lower bound.

Therefore We can make the triangle have an area smaller than 10
Choice B

Since we cases for Choice A and Choice B

Final Answer: D
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Re: GRE Math Challenge #109- The area of region OPQ or 10 [#permalink] New post 21 Aug 2020, 07:18
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sandy wrote:
Attachment:
#greprepclub PQ=OA=5.jpg


\(PQ=OQ=5\)

Quantity A
Quantity B
The area of region \(OPQ\)
\(10\)



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation


Let \(P\) be \((x,y)\).
We can assume \(-5 \le y \le 5\).
Then we have \(0 \le |y| \le 5\).
The area of the triangle \(OPQ\) is \(\frac{1}{2} \cdot 5|y|\) since its base is \(5\) and its height is \(|y|\).
We have \(0 \le \frac{1}{2} \cdot 5|y| \le \frac{1}{2} \cdot 5 \cdot 5 = \frac{25}{2}\), since \(0 \le |y| \le 5\).

If \(y = 5\), then its area is \(\frac{25}{2}\), which is greater than \(10\).
If \(y = 1\), then its area is \(\frac{1}{2} \cdot 5 \cdot 1 = \frac{5}{2}\), which is less than \(10\).

Therefore, the right answer is D.

Last edited by AskMathQuestions on 22 Aug 2020, 17:32, edited 1 time in total.
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Re: GRE Math Challenge #109- The area of region OPQ or 10 [#permalink] New post 22 Aug 2020, 15:32
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We know that \(PQ = 5\) and \(OQ = 5\), so those sides are fixed. But let's pretend we can grab point \(P\) with our fingertips and rotate it around while conserving the lengths of 5. This action would change the length of \(PO\).

We can certainly drag \(P\) so that \(PQ\) is perpendicular to \(OQ\), making it a right triangle. That would maximize the area at:

\(\frac{5*5}{2} = 12.5\)

However, we can drag point \(P\) to the right of point \(Q\) towards the x-axis and almost flatten it to a line, or go the opposite way towards point \(O\). In that case we'd be shrinking the area towards zero.

So the range of our area is:

\(0 < Area <= 12.5\)

The answer is therefore D.

As an aside, playing with that point \(P\) you'll get to see why rotating it to become perpendicular maximizes the area. It's the greatest height any triangle can have. Remembering that property and being able to visually see the changing area as you rotate \(P\) is valuable come test day.
Re: GRE Math Challenge #109- The area of region OPQ or 10   [#permalink] 22 Aug 2020, 15:32
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