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# GRE Math Challenge #102- x<y<20

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GRE Math Challenge #102- x<y<20 [#permalink]  09 May 2015, 11:21
Expert's post
00:00

Question Stats:

91% (00:29) correct 8% (00:40) wrong based on 98 sessions
$$x<y<20$$

Quantity A: $$x + y$$
Quantity B: 35
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
[Reveal] Spoiler: OA

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Sandy
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Re: GRE Math Challenge #102 [#permalink]  12 May 2015, 08:45
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Expert's post
sandy wrote:
$$x<y<20$$

Quantity A: x + y
Quantity B: 35

One of my favorite QC strategies is called "Looking for Equality" (free video on this topic here: http://www.greenlighttestprep.com/modul ... on?id=1099).
In this strategy, I first look for values of x and y such that the quantities A and B are equal.

Consider these two cases:
Case #1: x = 17 and y = 18
Quantity A: x + y = 17 + 18 = 35
Quantity B: 35
Since the two quantities are EQUAL, the correct answer is EITHER C or D

Now try some other values of x and y:
Case #2: x = 1 and y = 2
Quantity A: x + y = 1 + 2 = 3
Quantity B: 35
Since the two quantities are NOT EQUAL, the correct answer is D

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com

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Re: GRE Math Challenge #102- x<y<20 [#permalink]  11 Aug 2018, 12:58
sandy wrote:
$$x<y<20$$

Quantity A: $$x + y$$
Quantity B: 35
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined

x<y<20.

Note: we don't know whether x and y are positive or negative . Both can be positive or negative or combination. So, we don't have specific data here. Answer will vary for these reasons. At the same time we don't know whether they are consecutive or not.

Re: GRE Math Challenge #102- x<y<20   [#permalink] 11 Aug 2018, 12:58
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