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# GRE Math Challenge #1-x is an integer, and 169 < x^2 < 324

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GRE Math Challenge #1-x is an integer, and 169 < x^2 < 324 [#permalink]  06 Aug 2014, 13:47
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Question Stats:

53% (00:43) correct 46% (00:45) wrong based on 30 sessions
Level 170 question

If x is an integer, and $$169 < x^2 < 324$$, which of the following is the sum of all values of x?

(A) 61

(B) 62

(C) 75

(D) 93

(E) None of the above.
[Reveal] Spoiler: OA

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Re: GRE Math Challenge #1 [#permalink]  06 Aug 2014, 23:45
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Correct answer is 0, Hence (E).
x = {-17,-16,-15,-14,14,15,16,17}, Sum of all values = 0
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Re: GRE Math Challenge #1-x is an integer, and 169 < x^2 < 324 [#permalink]  20 Dec 2017, 06:21
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Expert's post
soumya1989 wrote:
Level 170 question

If x is an integer, and $$169 < x^2 < 324$$, which of the following is the sum of all values of x?

(A) 61

(B) 62

(C) 75

(D) 93

(E) None of the above.

We are given that 169 < x^2 < 324. That is, 13 < |x| < 18. If x is positive, x = 14, 15, 16, 17. If x is negative, x = -14, -15, -16, -17. We see that for every positive value of x, the opposite (or negative) is also a possibility. Thus, the sum of all values of x will be zero.

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Re: GRE Math Challenge #1-x is an integer, and 169 < x^2 < 324   [#permalink] 20 Dec 2017, 06:21
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# GRE Math Challenge #1-x is an integer, and 169 < x^2 < 324

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