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GRE Math Challenge #1- Given that y>4

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GRE Math Challenge #1- Given that y>4 [#permalink] New post 29 May 2014, 01:42
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A
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D
E

Difficulty:

  5% (low)

Question Stats:

100% (01:42) correct 0% (00:00) wrong based on 10 sessions
y>4

Quantity A

(3y + 2)/5

Quantity B

y

(A) Quantity A is greater.
(B) Quantity B is greater.
(C) The two quantities are equal.
(D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: GRE Math Challenge #1- Given that y>4 [#permalink] New post 16 Mar 2017, 01:10
D?

I solved this by plugging in. If y is 5, then A is greater but if Y is 4.1, then B is greater. Hence, D.
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Re: GRE Math Challenge #1- Given that y>4 [#permalink] New post 25 Mar 2017, 05:42
Expert's post
soumya1989 wrote:
y>4

Quantity A

(3y + 2)/5

Quantity B

y



Let's use the strategy of Matching Operations

Given:
Quantity A: (3y + 2)/5
Quantity B: y

Multiply both quantities by 5:
Quantity A: 3y + 2
Quantity B: 5y

Subtract 3y from both quantities:
Quantity A: 2
Quantity B: 2y

Divide both quantities by 2:
Quantity A: 1
Quantity B: y

Since we're told that y > 4, we can be certain that Quantity B is greater.

Answer:
[Reveal] Spoiler:
B


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Re: GRE Math Challenge #1- Given that y>4 [#permalink] New post 25 Mar 2017, 05:44
Expert's post
annyo wrote:
D?

I solved this by plugging in. If y is 5, then A is greater but if Y is 4.1, then B is greater. Hence, D.


If y = 5, we get:
Quantity A: [3(5) + 2]/5
Quantity B: 5

Simplify to get:
Quantity A: 3.4
Quantity B: 5

So, Quantity B is greater (not Quantity A).
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Re: GRE Math Challenge #1- Given that y>4   [#permalink] 25 Mar 2017, 05:44
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