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GRE Prep Club Legend  Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 105

Kudos [?]: 1783 , given: 397

g(x) = x2 – 4 and g(c) = 12. If c < 0, what is the value of [#permalink]
Expert's post 00:00

Question Stats: 33% (00:30) correct 66% (00:13) wrong based on 3 sessions
$$g(x) = x^2 - 4$$ and $$g(c) = 12$$. If c < 0, what is the value of $$g(c - 2)$$?

[Reveal] Spoiler: OA
32

_________________

Sandy
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GRE Prep Club Legend  Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 105

Kudos [?]: 1783 , given: 397

Re: g(x) = x2 – 4 and g(c) = 12. If c < 0, what is the value of [#permalink]
Expert's post
Explanation

For the function $$g(x) = x^2 - 4$$, plugging c in for x gives the answer 12. Thus:

$$c^2 - 4 = 12$$
$$c^2 = 16$$
$$c = 4$$ or $$-4$$

The problem indicates that c < 0, so c must be –4.

The problem then asks for $$g(c - 2)$$. Since $$c = -4$$, $$c - 2 = -6$$.

Plug –6 into the function:

$$g(-6) = (-6)^2 - 4$$

$$g(-6) = 36 - 4 = 32$$
_________________

Sandy
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Try our free Online GRE Test Re: g(x) = x2 – 4 and g(c) = 12. If c < 0, what is the value of   [#permalink] 02 Aug 2018, 06:37
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