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Retired Moderator Joined: 07 Jun 2014
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GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
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Expert's post 00:00

Question Stats: 100% (02:39) correct 0% (00:00) wrong based on 9 sessions
$$(\frac{1}{2})^3+(\frac{2}{3})^2+(\frac{1}{6})^1$$

A. $$\frac{1}{6}$$
B. $$\frac{1}{18}$$
C. $$\frac{5}{36}$$
D. $$\frac{53}{72}$$
E. $$\frac{8}{3}$$
[Reveal] Spoiler: OA

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Sandy
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Manager Joined: 29 Nov 2017
Posts: 190
Location: United States
GRE 1: Q142 V146 WE: Information Technology (Computer Software)
Followers: 1

Kudos [?]: 93 , given: 99 Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 171

Kudos [?]: 2911  , given: 394

1
KUDOS
Expert's post
this is one of those questions on the GRE whose sole purpose is to waste time.

Now this is a very basic arithmatic problem

$$(\frac{1}{2})^3 + (\frac{2}{3})^2 + \frac{1}{6}$$

$$\frac{1}{8} + \frac{4}{9} + \frac{1}{6}$$

$$\frac{9}{72} + \frac{32}{72} + \frac{12}{72}$$=$$53/72$$

Now this takes valueable seconds. If you are well versed with numbers start replacing fractions with approx values in decimals

$$\frac{1}{8} + \frac{4}{9} + \frac{1}{6}$$

$$\frac{1}{8}=0.125$$
$$\frac{4}{9} \approx 0.5$$
$$\frac{1}{6} \approx 0.15$$

Henc the total value must be greater than 0.5.

Opton D is only one that fits.
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Sandy
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Try our free Online GRE Test Re: fraction problem   [#permalink] 26 May 2018, 00:28
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