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For the positive integers a, b, c, and d, a is half of b, wh [#permalink]
23 Jun 2018, 12:24
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For the positive integers a, b, c, and d, a is half of b, which is onethird of c. The value of d is three times the value of c.
Quantity A 
Quantity B 
\(\frac{a+b}{c}\) 
\(\frac{a+b+c}{d}\) 
A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.
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Re: For the positive integers a, b, c, and d, a is half of b, wh [#permalink]
23 Jun 2018, 12:37
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sandy wrote: For the positive integers a, b, c, and d, a is half of b, which is onethird of c. The value of d is three times the value of c.
Quantity A 
Quantity B 
\(\frac{a+b}{c}\) 
\(\frac{a+b+c}{d}\) 
A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given. As per the statement Let b= 4 so that a= 2 , c = 12 and d=36 Therefore for statement 1 we have= \(\frac{6}{12} = \frac{1}{2}\) For statement 2 we have \(\frac{18}{36} = \frac{1}{2}\) So option C
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Re: For the positive integers a, b, c, and d, a is half of b, wh [#permalink]
18 Jul 2018, 07:07
ExplanationThe following relationships are given: \(a =\frac{b}{2}\), \(b = \frac{c}{3}\) , and d = 3c. Pick one variable and put everything in terms of that variable. For instance, variable a: b = 2a c = 3b = 3(2a) = 6a d = 3c = 3(6a) = 18a Substitute into the quantities and simplify. Quantity A: \(\frac{a+b}{c}=\frac{a+2a}{6a}=\frac{1}{2}\) Quantity B: \(\frac{a+b+c}{d}=\frac{a+2a+6a}{18a}=\frac{1}{2}\). The two quantities are equal.
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Re: For the positive integers a, b, c, and d, a is half of b, wh
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18 Jul 2018, 07:07





