Explanation

We don't need to solve this problem just know the definition of a Median. If a list of numbers are arranged in ascending order then it is the number in the exact middle.

If there are even number of terms then Median is the average of the two numbers in the middle.

So if the cars were arranges in increasing order of price Median would be the 16th Car.

The 16th car falls in the price range $5000 to $7499.

So its price can be anywhere between $5000 to $7499. All the options that satisfy this condition are correct.

Hence option A, B, C are correct.
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If there's an ODD number of values, the median is the MIDDLEMOST value when the numbers are arranged in ASCENDING ORDER.
There are 31 prices, so the median will be the 16th price, when all 31 prices are arranged in ASCENDING ORDER.
We can list the values in terms of their ranges.
The cheapest range is "under $5000" and there are 7 prices in this range.
So, if we list these prices, we get: under $5000, under $5000, under $5000, under $5000, under $5000, under $5000, under $5000,
We need to add more prices to get to 16th price (in ascending order)

The next price range is "$5000-$7499"
There are 10 such prices
Add these to our ASCENDING list: under $5000, under $5000, under $5000, under $5000, under $5000, under $5000, under $5000, $5000-$7499, $5000-$7499, $5000-$7499, $5000-$7499, $5000-$7499, $5000-$7499, $5000-$7499, $5000-$7499, $5000-$7499, $5000-$7499,

The 16th price in the list is $5000-$7499, so the median price can be ANY price in the range $5000 to $7499
So, possible medians include $5,500, $6,500 and $7,000

Answer:

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Here total number of sold cars is 31.
so the median number of the car is 16.
in which ever range is 16th number car is that will be the answer.
16th number car lies in 5000-7499 range.
So A, B and C is the answer.

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