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For all values of the integer p such that 1.9 < |p| < 5.3

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For all values of the integer p such that 1.9 < |p| < 5.3 [#permalink] New post 12 Aug 2018, 09:48
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For all values of the integer p such that \(1.9 < |p| < 5.3\), the function \(f(p) = p^2\) .

Quantity A
Quantity B
f(p) for the greatest value of p
f(p) for the least value of p


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

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[Reveal] Spoiler: OA

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Re: For all values of the integer p such that 1.9 < |p| < 5.3 [#permalink] New post 13 Aug 2018, 06:32
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Least value of p = -4 -> |p| = 4

Greatest value of p = 4 -> |p| = 4

f(-4) = f(4) = 16

So the answer is C.
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Re: For all values of the integer p such that 1.9 < |p| < 5.3 [#permalink] New post 16 Aug 2018, 14:38
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Why is the greatest value for p 4 and not 5?

Thank you :)
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Re: For all values of the integer p such that 1.9 < |p| < 5.3 [#permalink] New post 17 Aug 2018, 05:06
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In fact, in the range the least and the greatest values are -5 and 5 for which \(f(p)=p^2\).

4 is wrong. incidentally, the answer is still C but the value considered in the range is wrong.

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Re: For all values of the integer p such that 1.9 < |p| < 5.3 [#permalink] New post 01 Sep 2018, 08:47
Carcass wrote:
In fact, in the range the least and the greatest values are -5 and 5 for which \(f(p)=p^2\).

4 is wrong. incidentally, the answer is still C but the value considered in the range is wrong.

Regards



how come -5 it is 1.9 < |p| < 5.3..please elaborate.
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Re: For all values of the integer p such that 1.9 < |p| < 5.3 [#permalink] New post 01 Sep 2018, 10:17
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it is still -5 that into the absolute value becomes +5 and as it turns out: the least value is at the same time the GREATEST value in the range.

Hope this helps.

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Re: For all values of the integer p such that 1.9 < |p| < 5.3 [#permalink] New post 10 Sep 2018, 09:35
from the inequality, and the properties of absolute values, we can say that p has two separate/disjoint ranges of values: (-5.3, -1.9) and (1.9, 5.3).

so the lowest and the highest values p can take are -5.3 and 5.3, both of which give the same result when plugged into the function.

so the answer is C.
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Re: For all values of the integer p such that 1.9 < |p| < 5.3 [#permalink] New post 10 Sep 2018, 09:43
Carcass wrote:
For all values of the integer p such that \(1.9 < |p| < 5.3\), the function \(f(p) = p^2\) .

Quantity A
Quantity B
f(p) for the greatest value of p
f(p) for the least value of p


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

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Re: For all values of the integer p such that 1.9 < |p| < 5.3 [#permalink] New post 04 Mar 2020, 14:18
So basically because it's absolute value we must take the highest in the range as both a positive and a negative?
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Re: For all values of the integer p such that 1.9 < |p| < 5.3 [#permalink] New post 04 Mar 2020, 16:15
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Yes. Basic rule

See the attachment for all the math concepts you do need

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GMAT Club Math Book v3 - Jan-2-2013.pdf [2.83 MiB]
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Re: For all values of the integer p such that 1.9 < |p| < 5.3   [#permalink] 04 Mar 2020, 16:15
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For all values of the integer p such that 1.9 < |p| < 5.3

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