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For all real numbers, let a^* = 1 - a

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For all real numbers, let a^* = 1 - a [#permalink] New post 18 Mar 2018, 10:45
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77% (00:26) correct 22% (00:32) wrong based on 9 sessions
For all real numbers, let \(a^* = 1 - a\)

Quantity A
Quantity B
\(((-1)^*)^*\)
\(2^*\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: For all real numbers, let a^* = 1 - a [#permalink] New post 19 Mar 2018, 16:24
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Answer: C
a* = 1 - a
(-1)* = 1 - (-1) = 2 so ((-1)*)* = 2*
So A and B are equal. And answer is C.
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Re: For all real numbers, let a^* = 1 - a [#permalink] New post 20 Mar 2018, 00:31
Need some help here. I solved it this way:

A --> [(-1)^(1-1)]^(1-1) --> [(-1)^1+1]^1+1 --> (1)^2 --> 1
B --> 2^(2-1) = 2

So, B > A.

is this right?
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Re: For all real numbers, let a^* = 1 - a [#permalink] New post 20 Mar 2018, 04:07
Expert's post
Madhavi1990 wrote:
Need some help here. I solved it this way:

A --> [(-1)^(1-1)]^(1-1) --> [(-1)^1+1]^1+1 --> (1)^2 --> 1
B --> 2^(2-1) = 2

So, B > A.

is this right?


No \(a^{*}=1-a\)
so \(2^{*}=1-2=-1\) not \(2^{*}=2^{2-1}\)
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Re: For all real numbers, let a^* = 1 - a   [#permalink] 20 Mar 2018, 04:07
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