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# For all real numbers, let a^* = 1 - a

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For all real numbers, let a^* = 1 - a [#permalink]  18 Mar 2018, 10:45
Expert's post
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Question Stats:

77% (00:26) correct 22% (00:32) wrong based on 9 sessions
For all real numbers, let $$a^* = 1 - a$$

 Quantity A Quantity B $$((-1)^*)^*$$ $$2^*$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: For all real numbers, let a^* = 1 - a [#permalink]  19 Mar 2018, 16:24
1
KUDOS
a* = 1 - a
(-1)* = 1 - (-1) = 2 so ((-1)*)* = 2*
So A and B are equal. And answer is C.
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Re: For all real numbers, let a^* = 1 - a [#permalink]  20 Mar 2018, 00:31
Need some help here. I solved it this way:

A --> [(-1)^(1-1)]^(1-1) --> [(-1)^1+1]^1+1 --> (1)^2 --> 1
B --> 2^(2-1) = 2

So, B > A.

is this right?
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Re: For all real numbers, let a^* = 1 - a [#permalink]  20 Mar 2018, 04:07
Expert's post
Need some help here. I solved it this way:

A --> [(-1)^(1-1)]^(1-1) --> [(-1)^1+1]^1+1 --> (1)^2 --> 1
B --> 2^(2-1) = 2

So, B > A.

is this right?

No $$a^{*}=1-a$$
so $$2^{*}=1-2=-1$$ not $$2^{*}=2^{2-1}$$
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Re: For all real numbers, let a^* = 1 - a   [#permalink] 20 Mar 2018, 04:07
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# For all real numbers, let a^* = 1 - a

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