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For all nonzero integers l and m, let the operation § be def [#permalink]
26 Mar 2018, 15:51

Expert's post

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Question Stats:

100% (00:25) correct
0% (00:00) wrong based on 9 sessions

For all nonzero integers l and m, let the operation § be defined by l § m \(= - \mid \frac{l+m}{lm} \mid\).

Quantity A

Quantity B

3§ \(\frac{3}{2}\)

-1

A. Quantity A is greater. B. Quantity B is greater. C. The two quantities are equal. D. The relationship cannot be determined from the information given.

Re: For all nonzero integers l and m, let the operation § be def [#permalink]
04 Apr 2018, 04:18

1

This post received KUDOS

In a fake function problem like this we simply need to follow their instructions. In this case, add the terms on either side of the §, then multiply them and divide the former result by the latter result. Then get its absolute value and slap a minus sign on the whole thing. Let's do it.

In quantity A, for the numerator:

3 + 3/2 = 9/2

For the denominator:

3x(3/2) = 9/2

If we divide 3/2 by 3/2 obviously we'll get 1. Since -|1| = -1, the answer must be C.
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