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# For all nonzero integers l and m, let the operation § be def

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GRE Prep Club Legend
Joined: 07 Jun 2014
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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Kudos [?]: 1897 [0], given: 397

For all nonzero integers l and m, let the operation § be def [#permalink]  26 Mar 2018, 15:51
Expert's post
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Question Stats:

100% (00:25) correct 0% (00:00) wrong based on 9 sessions
For all nonzero integers l and m, let the operation § be defined by l § m $$= - \mid \frac{l+m}{lm} \mid$$.

 Quantity A Quantity B 3§ $$\frac{3}{2}$$ -1

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.

Drill 2
Question: 3
Page: 549
[Reveal] Spoiler: OA

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Sandy
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Manager
Joined: 15 Jan 2018
Posts: 147
GMAT 1: Q V
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Kudos [?]: 185 [1] , given: 0

Re: For all nonzero integers l and m, let the operation § be def [#permalink]  04 Apr 2018, 04:18
1
KUDOS
In a fake function problem like this we simply need to follow their instructions. In this case, add the terms on either side of the §, then multiply them and divide the former result by the latter result. Then get its absolute value and slap a minus sign on the whole thing. Let's do it.

In quantity A, for the numerator:

3 + 3/2 = 9/2

For the denominator:

3x(3/2) = 9/2

If we divide 3/2 by 3/2 obviously we'll get 1. Since -|1| = -1, the answer must be C.
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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4810
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 118

Kudos [?]: 1897 [1] , given: 397

Re: For all nonzero integers l and m, let the operation § be def [#permalink]  04 Apr 2018, 15:59
1
KUDOS
Expert's post
Explanation

When a problem gives you a relationship signified by an unfamiliar symbol: Just plug in the given values into the given “function” and solve.

If l § m=$$-|\frac{l+m}{lm}|$$ then 3 §$$\frac{3}{2}$$=$$-|\frac{3+ 1.5}{3 \times 1.5}|=-1$$.

The quantities are equal, so select choice (C).
_________________

Sandy
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Re: For all nonzero integers l and m, let the operation § be def   [#permalink] 04 Apr 2018, 15:59
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