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For all integers a and b, a # b = –|a + b|

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For all integers a and b, a # b = –|a + b| [#permalink] New post 10 Jun 2017, 02:16
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For all integers a and b, a # b = –|a + b|

Quantity A
Quantity B
(–10) # 7
7 – 10



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: For all integers a and b, a # b = –|a + b| [#permalink] New post 10 Jun 2017, 12:49
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Carcass wrote:


For all integers a and b, a # b = –|a + b|

Quantity A
Quantity B
(–10) # 7
7 – 10



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



a # b = –|a + b|
So, (–10) # 7 = –|(-10) + 7|
= -|-3|
= -(3)
= -3

So, we get:
Quantity A: -3
Quantity B: 7 - 10

Answer:
[Reveal] Spoiler:
C


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Re: For all integers a and b, a # b = –|a + b| [#permalink] New post 01 Feb 2018, 00:15
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Given that, all integers a and b, a # b = –|a + b|
Q.A (–10) # 7 = - |-10+7| = - |-3| = -3
Q.B 7-10 = -3

So the answer is C
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Re: For all integers a and b, a # b = –|a + b| [#permalink] New post 17 Feb 2018, 02:09
Answer is clearly C
It's an easy question.
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Re: For all integers a and b, a # b = –|a + b| [#permalink] New post 17 Feb 2018, 15:58
GREMasterBlaster wrote:
Answer is clearly C
It's an easy question.


easy to get tripped up, since the intergers used are A and B, and the option choices are A and B
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Re: For all integers a and b, a # b = –|a + b| [#permalink] New post 17 Aug 2018, 19:35
Since |a|=-a when a<0, Shouldn't we also test for -(-|-10+7|) which gives us 3. Hence it could be -3 or 3 isn't it? Thanks for the clarification.
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Re: For all integers a and b, a # b = –|a + b| [#permalink] New post 18 Aug 2018, 02:16
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in a#b you just need to substitute.

a = -10 and b = 7

QA - |a+b|= - |-3|= - |3| (insde the absolute value) = -3

QB is -3

Answer is c
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Re: For all integers a and b, a # b = –|a + b|   [#permalink] 18 Aug 2018, 02:16
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