almondspeeing wrote:

Can someone please explain this?

Here

A chart of relative frequency of the numbers are given, please be informed they are not the actual frequency. The total of the relative frequencies will always be 1 or 100%

So when it says that the relative frequency of 2 is 0.10, that means that 2 occurs ten percent of the time.

Hence to find out the mean, let's calculate

\(\frac{[(0*18)+(1*33)+(2*10)+(3*6)+(4*33)]}{100}= \frac{203}{100} = 2.03\)

B) As per the table,

When x = 0, the relative frequency = 0.18, i.e. 0 occurs 18% of the time and similarly 1 occurs 33% of time

so 18 + 33 = 51, we are in the middle range and hence median = 1

You can also read more about distribution here::

https://www.mathsisfun.com/data/frequen ... ution.html
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