It is currently 15 Sep 2019, 10:04
My Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Find the mean and median of the values of the random variabl

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Founder
Founder
User avatar
Joined: 18 Apr 2015
Posts: 8061
Followers: 155

Kudos [?]: 1682 [0], given: 7386

CAT Tests
Find the mean and median of the values of the random variabl [#permalink] New post 30 May 2019, 10:30
Expert's post
Find the mean and median of the values of the random variable X, whose relative frequency distribution is given in the table below.

Attachment:
#GREexcercise Find the mean and median of the values.jpg
#GREexcercise Find the mean and median of the values.jpg [ 17.71 KiB | Viewed 792 times ]


[Reveal] Spoiler: OA
mean=2.03, median=1


Math Review
Question: 4
Page: 296
Difficulty: medium

_________________

Get the 2 FREE GREPrepclub Tests

Intern
Intern
Joined: 06 Feb 2019
Posts: 16
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: Find the mean and median of the values of the random variabl [#permalink] New post 16 Jun 2019, 20:22
Can someone please explain this?
1 KUDOS received
Director
Director
Joined: 20 Apr 2016
Posts: 990
WE: Engineering (Energy and Utilities)
Followers: 14

Kudos [?]: 782 [1] , given: 165

CAT Tests
Re: Find the mean and median of the values of the random variabl [#permalink] New post 16 Jun 2019, 22:20
1
This post received
KUDOS
almondspeeing wrote:
Can someone please explain this?



Here

A chart of relative frequency of the numbers are given, please be informed they are not the actual frequency. The total of the relative frequencies will always be 1 or 100%

So when it says that the relative frequency of 2 is 0.10, that means that 2 occurs ten percent of the time.

Hence to find out the mean, let's calculate

\(\frac{[(0*18)+(1*33)+(2*10)+(3*6)+(4*33)]}{100}= \frac{203}{100} = 2.03\)

B) As per the table,

When x = 0, the relative frequency = 0.18, i.e. 0 occurs 18% of the time and similarly 1 occurs 33% of time

so 18 + 33 = 51, we are in the middle range and hence median = 1

You can also read more about distribution here:: https://www.mathsisfun.com/data/frequen ... ution.html
_________________

If you found this post useful, please let me know by pressing the Kudos Button


Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html

Display posts from previous: Sort by

Find the mean and median of the values of the random variabl

  Question banks Downloads My Bookmarks Reviews Important topics  


GRE Prep Club Forum Home| About| Terms and Conditions and Privacy Policy| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.