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Find the greatest integer:
[#permalink]
Updated on: 29 Oct 2017, 09:26

1

2

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Question Stats:

Find the greatest integer

a) \(10^{10} + 2^{100}\)

b) \(100^{10} + 2^{10}\)

c) \((100 + 2 ) ^{10}\)

Can anyone suggest me the efficient way to solve this question?

a) \(10^{10} + 2^{100}\)

b) \(100^{10} + 2^{10}\)

c) \((100 + 2 ) ^{10}\)

Can anyone suggest me the efficient way to solve this question?

Re: Find the greatest integer:
[#permalink]
01 Nov 2017, 19:12

2

Expert Reply

sandesh10 wrote:

Find the greatest integer

a) \(10^{10} + 2^{100}\)

b) \(100^{10} + 2^{10}\)

c) \((100 + 2 ) ^{10}\)

Can anyone suggest me the efficient way to solve this question?

a) \(10^{10} + 2^{100}\)

b) \(100^{10} + 2^{10}\)

c) \((100 + 2 ) ^{10}\)

Can anyone suggest me the efficient way to solve this question?

Hi...

The easiest way would be..

Compare a and B..

a) \(10^{10} + 2^{100}\)

b) \(100^{10} + 2^{10}= (10^{10})^{10}+2^{10}=10^{100}+2^{10}\)

Now when you compare two 10^{100} is way GREATER than 2^{100} as compared to 10^{10} and 2^{10} ..

Otherwise a exact way would be...

a) \(10^{10} + 2^{100}=10^{10}+(2^{10})^10=10^{10}+1024^{10}=10^{10}+10^{30}~10^30\)

b) \(100^{10} + 2^{10}=10^{100}+10^3\)

SO B is clearly the bigger one

Now let's compare B and C

c) \((100 + 2 ) ^{10}\)

When you expand it 100^{10}+100^9*2^1+.....+2^10

So here C is bigger..

Also

b) \(100^{10} + 2^{10}~100^{10}\)

c) \((100 + 2 ) ^{10}=102^{10}\)

C wins

_________________

Some useful Theory.

1. Arithmetic and Geometric progressions : https://greprepclub.com/forum/progressions-arithmetic-geometric-and-harmonic-11574.html#p27048

2. Effect of Arithmetic Operations on fraction : https://greprepclub.com/forum/effects-of-arithmetic-operations-on-fractions-11573.html?sid=d570445335a783891cd4d48a17db9825

3. Remainders : https://greprepclub.com/forum/remainders-what-you-should-know-11524.html

4. Number properties : https://greprepclub.com/forum/number-property-all-you-require-11518.html

5. Absolute Modulus and Inequalities : https://greprepclub.com/forum/absolute-modulus-a-better-understanding-11281.html

1. Arithmetic and Geometric progressions : https://greprepclub.com/forum/progressions-arithmetic-geometric-and-harmonic-11574.html#p27048

2. Effect of Arithmetic Operations on fraction : https://greprepclub.com/forum/effects-of-arithmetic-operations-on-fractions-11573.html?sid=d570445335a783891cd4d48a17db9825

3. Remainders : https://greprepclub.com/forum/remainders-what-you-should-know-11524.html

4. Number properties : https://greprepclub.com/forum/number-property-all-you-require-11518.html

5. Absolute Modulus and Inequalities : https://greprepclub.com/forum/absolute-modulus-a-better-understanding-11281.html

Re: Find the greatest integer:
[#permalink]
14 Jun 2019, 06:57

chetan2u wrote:

sandesh10 wrote:

Find the greatest integer

a) \(10^{10} + 2^{100}\)

b) \(100^{10} + 2^{10}\)

c) \((100 + 2 ) ^{10}\)

Can anyone suggest me the efficient way to solve this question?

a) \(10^{10} + 2^{100}\)

b) \(100^{10} + 2^{10}\)

c) \((100 + 2 ) ^{10}\)

Can anyone suggest me the efficient way to solve this question?

Hi...

The easiest way would be..

Compare a and B..

a) \(10^{10} + 2^{100}\)

b) \(100^{10} + 2^{10}= (10^{10})^{10}+2^{10}=10^{100}+2^{10}\)

Now when you compare two 10^{100} is way GREATER than 2^{100} as compared to 10^{10} and 2^{10} ..

Otherwise a exact way would be...

a) \(10^{10} + 2^{100}=10^{10}+(2^{10})^10=10^{10}+1024^{10}=10^{10}+10^{30}~10^30\)

b) \(100^{10} + 2^{10}=10^{100}+10^3\)

SO B is clearly the bigger one

Now let's compare B and C

c) \((100 + 2 ) ^{10}\)

When you expand it 100^{10}+100^9*2^1+.....+2^10

So here C is bigger..

Also

b) \(100^{10} + 2^{10}~100^{10}\)

c) \((100 + 2 ) ^{10}=102^{10}\)

C wins

for option b,

100^10+2^10=> (10^2)^10+2^10=>10^20+2^10.

Isn't it ?

Re: Find the greatest integer:
[#permalink]
07 Nov 2021, 10:32

Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.

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