Carcass wrote:
Find an algebraic expression to represent each of the following.
(a) The square of y is subtracted from 5, and the result is multiplied by 37.
(b) Three times x is squared, and the result is divided by 7.
(c) The product of \((x+4)\) and y is added to 18.
(a) \(37(5-y^2)\), or \(185-37y^2\) (b) \(\frac{(3x)^2}{7}\), or \(\frac{9x^2}{7}\) (c) \(18+ (x+4)(y)\), or \(18+xy+4y\)
Math Review
Question: 1
Page: 243
Difficulty: medium
(a) The square of y is subtracted from 5, and the result is multiplied by 37.
The square of y is subtracted from 5: \(5-y^2\)
...and the result is multiplied by 37: \(37(5-y^2)\)
(b) Three times x is squared, and the result is divided by 7.
Three times x is squared: \((3x)^2\)
...and the result is divided by 7: \(\frac{(3x)^2}{7}\)
(c) The product of \((x+4)\) and y is added to 18.
The product of \((x+4)\) and y: \(y(x+4)\)
...is added to 18: \(18+y(x+4)\)
If we want, we can also expand the product to get: \(18+yx+4y\)
Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
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23 May 2019, 01:16
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