Carcass wrote:

Find an algebraic expression to represent each of the following.

(a) The square of y is subtracted from 5, and the result is multiplied by 37.

(b) Three times x is squared, and the result is divided by 7.

(c) The product of \((x+4)\) and y is added to 18.

(a) \(37(5-y^2)\), or \(185-37y^2\) (b) \(\frac{(3x)^2}{7}\), or \(\frac{9x^2}{7}\) (c) \(18+ (x+4)(y)\), or \(18+xy+4y\)

Math Review

Question: 1

Page: 243

Difficulty: medium

(a) The square of y is subtracted from 5, and the result is multiplied by 37.

The square of y is subtracted from 5: \(5-y^2\)

...and the result is multiplied by 37: \(37(5-y^2)\)

(b) Three times x is squared, and the result is divided by 7.

Three times x is squared: \((3x)^2\)

...and the result is divided by 7: \(\frac{(3x)^2}{7}\)

(c) The product of \((x+4)\) and y is added to 18.

The product of \((x+4)\) and y: \(y(x+4)\)

...is added to 18: \(18+y(x+4)\)

If we want, we can also expand the product to get: \(18+yx+4y\)

Cheers,

Brent

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Brent Hanneson – Creator of greenlighttestprep.com

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