Solution


Here we have from the question fractions of faculty with tenure

Female	Male
1/3	2/9

Now taking the data from the graph we get

Female	Male
5% + 16% = 21%	10% + 8%= 18%
21% 0f 200	18% of 250
42	45

Thus we have the total number of faculty member. Now we need to find out the fraction with tenure

Female	Male
1/3 of 42	2/9 of 45
14	10

Thus the ratio of tenured to non tenures is \(\frac{(14 +10)}{(42 + 45)}\)=\(\frac{24}{87}\)
_________________

I took 3 mins 20 s to do this question.

Do not get discouraged.

The secret lies to read very carefully the stem and what the question is asking you.

All the information are there in the graph

Why can't we do the following:

#females bio: .05*200 = 10
#males bio: .16*250=20
likewise,
#females health: 40
# males health: 20

#tenured females in bio & health: (5)*1/3 = 16.667
#tenured males in bio & health: (20)*(2/9) = 4.444
#tenured females: (1/3)*200 = 66.66
#tenured males: (2/9)*250 = 55.55

Thus final ratio would be (16.667 + 4.44)/(66.66 + 55.55).

Please show me the fallacy in my logic.

Good! I'm as always not careful, so I had made a lot of unnecessary calculations.

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