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faculty combined, 1/3 of the female and 2/9 of the male

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Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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faculty combined, 1/3 of the female and 2/9 of the male [#permalink] New post 08 Jan 2016, 09:06
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Question Stats:

58% (03:15) correct 41% (04:22) wrong based on 12 sessions
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For the biological sciences and health sciences faculty combined, 1/3 of the female and 2/9 of the male faculty members are tenured professors. What
fraction of all the faculty members in those two fields combined are tenured professors?


Give Your Answer in Fraction:


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Question: 3
Page: 162
Difficulty: hard

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Joined: 07 Jun 2014
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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Kudos [?]: 1657 [2] , given: 396

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Re: faculty combined, 1/3 of the female and 2/9 of the male [#permalink] New post 08 Jan 2016, 19:38
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Solution


Here we have from the question fractions of faculty with tenure


Female Male
1/3 2/9


Now taking the data from the graph we get




Female Male
5% + 16% = 21% 10% + 8%= 18%
21% 0f 200 18% of 250
42 45


Thus we have the total number of faculty member. Now we need to find out the fraction with tenure



Female Male
1/3 of 42 2/9 of 45
14 10


Thus the ratio of tenured to non tenures is \(\frac{(14 +10)}{(42 + 45)}\)=\(\frac{24}{87}\)
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Re: faculty combined, 1/3 of the female and 2/9 of the male [#permalink] New post 09 Oct 2018, 01:49
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I took 3 mins 20 s to do this question. :(
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Re: faculty combined, 1/3 of the female and 2/9 of the male [#permalink] New post 09 Oct 2018, 09:36
Expert's post
Do not get discouraged.

The secret lies to read very carefully the stem and what the question is asking you.

All the information are there in the graph
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Re: faculty combined, 1/3 of the female and 2/9 of the male [#permalink] New post 09 Dec 2018, 12:11
Why can't we do the following:

#females bio: .05*200 = 10
#males bio: .16*250=20
likewise,
#females health: 40
# males health: 20

#tenured females in bio & health: (5)*1/3 = 16.667
#tenured males in bio & health: (20)*(2/9) = 4.444
#tenured females: (1/3)*200 = 66.66
#tenured males: (2/9)*250 = 55.55

Thus final ratio would be (16.667 + 4.44)/(66.66 + 55.55).

Please show me the fallacy in my logic.
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faculty combined, 1/3 of the female and 2/9 of the male

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