Solution


Here we have from the question fractions of faculty with tenure

Female	Male
1/3	2/9

Now taking the data from the graph we get

Female	Male
5% + 16% = 21%	10% + 8%= 18%
21% 0f 200	18% of 250
42	45

Thus we have the total number of faculty member. Now we need to find out the fraction with tenure

Female	Male
1/3 of 42	2/9 of 45
14	10

Thus the ratio of tenured to non tenures is \(\frac{(14 +10)}{(42 + 45)}\)=\(\frac{24}{87}\)
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I took 3 mins 20 s to do this question.

Do not get discouraged.

The secret lies to read very carefully the stem and what the question is asking you.

All the information are there in the graph
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Why can't we do the following:

#females bio: .05*200 = 10
#males bio: .16*250=20
likewise,
#females health: 40
# males health: 20

#tenured females in bio & health: (5)*1/3 = 16.667
#tenured males in bio & health: (20)*(2/9) = 4.444
#tenured females: (1/3)*200 = 66.66
#tenured males: (2/9)*250 = 55.55

Thus final ratio would be (16.667 + 4.44)/(66.66 + 55.55).

Please show me the fallacy in my logic.

Good! I'm as always not careful, so I had made a lot of unnecessary calculations.