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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # F is the midpoint of AE, and D is the midpoint of CE. Wh  Question banks Downloads My Bookmarks Reviews Important topics
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Moderator  Joined: 18 Apr 2015
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F is the midpoint of AE, and D is the midpoint of CE. Wh [#permalink]
Expert's post 00:00

Question Stats: 35% (01:21) correct 64% (02:14) wrong based on 17 sessions

Attachment: #GREpracticequestion F is the midpoint of AE, and D is the midpoint of CE.jpg [ 20.98 KiB | Viewed 559 times ]

F is the midpoint of AE, and D is the midpoint of CE.

Which of the following statements MUST be true?

Indicate all such statements.

❑ FD is parallel to AC.

❑ The area of triangle DEF equals the area of triangle CDF.

❑ The area of triangle ABF is less than the area of triangle DEF.

❑ Angle AFB equals angle BFC.

❑ The area of triangle ACE equals AC x BF.
[Reveal] Spoiler: OA

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Re: F is the midpoint of AE, and D is the midpoint of CE. Wh [#permalink]
Any hint for this question? Moderator  Joined: 18 Apr 2015
Posts: 5919
Followers: 96

Kudos [?]: 1159  , given: 5501

Re: F is the midpoint of AE, and D is the midpoint of CE. Wh [#permalink]
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Expert's post
A is right

Because DE is $$\frac{1}{2}$$ of CE and FE is $$\frac{1}{2}$$ of AE (i.e., corre­sponding sides have proportional lengths), and angle DEF is shared between /the two triangles, you can see that triangles ACE and FDE must be similar. Similar triangles have the further property that corresponding angles are of equal measure. Thus, for example, angle DFE equals angle CAE, and so FD is parallel to AC.

B is right

Looking at the two smaller triangles in the right half of the figure, you can see that triangle CD F and triangle DEF have collinear and equal “bases” (CD and DE), and share their third vertex (F), which is some fixed distance away from
CE. Because CE is comprised of bases CD and DE of triangles CD F and DEF, re­spectively, the two triangles have the same height. Because CDF and DEF have equal bases and the same height, they must have the same area. (For a similar rea­son, triangles ACF and FCE must have equal areas; more on that later.)

Choice E is right

Because triangles ACF and FCE must have equal areas as indicated above, you can see that the area of triangle ACE must be twice that of triangle ACF. Note that FD is parallel to AC due to (true) choice (A), and BF is perpendicular toFD. Therefore, BF must be perpendicular to AC as well. Put differently, AC can be regarded as the base, and BF the height, of triangle ACF. The area of triangle ACF equals ^ times AC x BF. The area of triangle ACE, which is twice that of ACF, must therefore equal AC x BF.
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Re: F is the midpoint of AE, and D is the midpoint of CE. Wh [#permalink]
Hello guys, any hint why choices C and D are false?
Moderator  Joined: 18 Apr 2015
Posts: 5919
Followers: 96

Kudos [?]: 1159 , given: 5501

Re: F is the midpoint of AE, and D is the midpoint of CE. Wh [#permalink]
Expert's post
if you redraw the figure as follow, then C and D not necessarily are true.

Attachment: triangle.png [ 35.83 KiB | Viewed 1433 times ]

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Re: F is the midpoint of AE, and D is the midpoint of CE. Wh [#permalink]
thanks Re: F is the midpoint of AE, and D is the midpoint of CE. Wh   [#permalink] 08 Jan 2019, 02:57
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