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Exponetial question n = 2^3 then n^n

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Exponetial question n = 2^3 then n^n [#permalink] New post 18 Jan 2016, 02:09
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Question Stats:

82% (00:28) correct 17% (00:31) wrong based on 67 sessions
If \(n=2^3\), then \(n^n=\)

A \(2^6\)

B \(2^{11}\)

C \(2^{18}\)

D \(2^{24}\)

E \(2^{27}\)

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Question: 22
Page: 335
Difficulty: easy
[Reveal] Spoiler: OA

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Retired Moderator
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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Kudos [?]: 2753 [2] , given: 394

Re: Exponetial question n = 2^3 then n^n [#permalink] New post 18 Jan 2016, 04:20
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Solution

In this question the answer choices are all in the form 2 raised to a power, so we should try to achieve that form. It is given that n=\(2^3\)=8.
Therefore, \(n^n\)=\((2^3)^8\)=\(2^2^4\). The correct answer is Choice D.
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Re: Exponetial question n = 2^3 then n^n [#permalink] New post 14 Jul 2016, 15:00
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RELATED VIDEO (starting at 3:45)

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Re: Exponetial question n = 2^3 then n^n   [#permalink] 14 Jul 2016, 15:00
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