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# Exactly 8 years ago, Jim’s son was twice as old as Jim’s

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Senior Manager
Joined: 20 May 2014
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Kudos [?]: 49 [0], given: 220

Exactly 8 years ago, Jim’s son was twice as old as Jim’s [#permalink]  17 Oct 2017, 22:25
00:00

Question Stats:

33% (00:00) correct 66% (01:42) wrong based on 3 sessions
Exactly 8 years ago, Jim’s son was twice as old as Jim’s daughter. If Jim’s son is now 5 years older than his daughter, how old is Jim’s daughter now?

(A) 5
(B) 10
(C) 13
(D) 16
(E) 18

Kudos for correct solution.
[Reveal] Spoiler: OA
Director
Joined: 03 Sep 2017
Posts: 521
Followers: 1

Kudos [?]: 332 [1] , given: 66

Re: Exactly 8 years ago, Jim’s son was twice as old as Jim’s [#permalink]  18 Oct 2017, 05:15
1
KUDOS
Calling S son's age and D daughter's age, we get

$$S-8 = 2(D-8)$$

$$S = D+5$$

Solving, D = 13. Answer C
Target Test Prep Representative
Affiliations: Target Test Prep
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Posts: 161
Location: United States
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Kudos [?]: 117 [0], given: 0

Re: Exactly 8 years ago, Jim’s son was twice as old as Jim’s [#permalink]  08 Jan 2018, 10:51
Expert's post
Bunuel wrote:
Exactly 8 years ago, Jim’s son was twice as old as Jim’s daughter. If Jim’s son is now 5 years older than his daughter, how old is Jim’s daughter now?

(A) 5
(B) 10
(C) 13
(D) 16
(E) 18

We can let Jim’s son’s current age = s and Jim’s daughter’s current age = d. We can also state that 8 years ago, his son was (s - 8) years old and his daughter was (d - 8) years old. We can create the following equation:

s - 8 = 2(d - 8)

s - 8 = 2d - 16

s = 2d - 8

and

s = 5 + d

Thus:

2d - 8 = 5 + d

d = 13

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Re: Exactly 8 years ago, Jim’s son was twice as old as Jim’s   [#permalink] 08 Jan 2018, 10:51
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# Exactly 8 years ago, Jim’s son was twice as old as Jim’s

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