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Every week, Renee is paid $40 per hour for the first 40 hour
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25 Aug 2018, 15:28
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75% (01:48) correct
24% (01:35) wrong based on 62 sessions
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Every week, Renee is paid $40 per hour for the first 40 hours she works, and $80 per hour for each hour she works after the first 40 hours. How many hours would Renee have to work in one week to earn an average (arithmetic mean) of $60 per hour that week?
Re: Every week, Renee is paid $40 per hour for the first 40 hour
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02 Sep 2018, 21:26
2
For the first 40 hrs she earns $40 per hr hence she should work for the first 40 hrs. Her income on that would be $1600 For each hr more she will earn $80. Hence, let the extra hrs she works be x then for that she earns 80x.
By question, \(\frac{80x + 1600}{40+x} = 60\) solve for x; x = 40 Therefore, total hrs she has to work for the week to earn $60 avg would be 80 hrs.
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Re: Every week, Renee is paid $40 per hour for the first 40 hour
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15 Oct 2018, 09:04
Renee makes $40*40 hours=$1600 in first 40 hours Let 't' be the no of hours Renee would work. Given, Renee makes $80 per hour for each hour she works after the first 40 hours. So, she makes an additional pay $80*(t-40)hours for every hour after 40 hours.
So, 1600+80(t−40)t=601600+80(t−40)t=60 Or, 1600+80t-3200=60t Or, 20t=1600 or, t=80 hours
Re: Every week, Renee is paid $40 per hour for the first 40 hour
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11 Jul 2019, 03:05
ruposh6240 wrote:
Edited:
Let 't' = number of hours Renee will have to work. Concept: The average rate Renee gets paid is equal to the total wages earned divided by the total number of hours worked. Rene earns\($40\) per hour for the first \(40\) hours, so she makes\(40 × 40\)= \($1,600\) in the first \(40\) hours. She also earns\($80\) for every hour after 40 hours, for additional pay of\($80(t – 40)\). Therefore, her total pay can be calculated as: