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Esteban’s restaurant offers a lunch special. A customer can

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GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4750
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1665 [0], given: 396

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Esteban’s restaurant offers a lunch special. A customer can [#permalink] New post 30 Dec 2017, 13:53
Expert's post
00:00

Question Stats:

66% (00:54) correct 33% (02:11) wrong based on 9 sessions
Esteban’s restaurant offers a lunch special. A customer can order a platter consisting of four different small dishes from a selection of twelve choices. How many different platters can a customer create?

A. 24
B. 144
C. 495
D. 11,880
E. 20,736

Drill 2
Question: 5
Page: 563
[Reveal] Spoiler: OA

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GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4750
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1665 [0], given: 396

CAT Tests
Re: Esteban’s restaurant offers a lunch special. A customer can [#permalink] New post 08 Jan 2018, 16:28
Expert's post
Explanation

This problem is about combinations, because the order of the dishes does not matter.

Since you’re choosing 4 dishes, start by drawing 4 blanks. On top, write the number of choices: 12 choices for the first dish, then 11, 10, and 9. On the bottom, start with the size of the smaller group and count down: 4, 3, 2, and 1.

Cancel the numbers on the bottom, and the numbers on top will multiply to 495.

Hence option C is correct!
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Intern
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Re: Esteban’s restaurant offers a lunch special. A customer can [#permalink] New post 03 Feb 2018, 04:03
Thank you.
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Re: Esteban’s restaurant offers a lunch special. A customer can [#permalink] New post 26 Mar 2018, 07:39
sandy wrote:
Explanation

This problem is about combinations, because the order of the dishes does not matter.

Since you’re choosing 4 dishes, start by drawing 4 blanks. On top, write the number of choices: 12 choices for the first dish, then 11, 10, and 9. On the bottom, start with the size of the smaller group and count down: 4, 3, 2, and 1.

Cancel the numbers on the bottom, and the numbers on top will multiply to 495.

Hence option C is correct!


Can you please explain in more detail?
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Re: Esteban’s restaurant offers a lunch special. A customer can [#permalink] New post 26 Mar 2018, 11:55
Expert's post
This a classic combinatorics problem, in which you count the 4 dishes from 12 (the order does not matter) and apply the classic formula.

\(\frac{12*11*10*9*8*7*6*5*4*3*2*1}{(8*7*6*5*4*3*2*1)*(4*3*2*1)} =\)

Simplify

\(3*11*5*3 = 495\)

C is the answer
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Re: Esteban’s restaurant offers a lunch special. A customer can   [#permalink] 26 Mar 2018, 11:55
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Esteban’s restaurant offers a lunch special. A customer can

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