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Equilater trinagle PQR is formed by joining [#permalink]
16 Mar 2018, 17:07
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Question Stats:
66% (00:43) correct
33% (00:55) wrong based on 128 sessions
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#GREpracticequestion Equilateral triangle PQR is formed by joining.jpg [ 17.91 KiB  Viewed 3246 times ]
Equilateral triangle PQR is formed by joining center P, Q, and R of the circles. Each pair of circles has exactly one point in common.
Quantity A 
Quantity B 
The perimeter of triangle PQR 
The circumference of the circle with center Q 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
Last edited by Carcass on 14 Jan 2019, 14:48, edited 3 times in total.
Edited the OA




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Re: Equilater trinagle PQR is formed by joining [#permalink]
17 Mar 2018, 23:34
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Is the answer B?
A: Let r be the radius of each circle. Each side of the equilateral triangle is 2r, so the perimeter is 6r.
B: Circumference of Q = 2 * 3.14 * r > 6r.
So the answer is B.



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Re: Equilater trinagle PQR is formed by joining [#permalink]
24 Apr 2018, 18:40
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From given info Rp + Rq = other two sides of the triangle So, perimeter will be 3(Rp+Rq) Now we have to compare 3Rp + 3Rq ? 2 Pi Rq
As we don't know the value of Rp so answer can not be determined.



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Re: Equilater trinagle PQR is formed by joining [#permalink]
12 May 2018, 06:01
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Should the answer be B for this question?



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Re: Equilater trinagle PQR is formed by joining [#permalink]
12 May 2018, 10:26
Sorry for the inconvenience. fixed. regards
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Re: Equilater trinagle PQR is formed by joining [#permalink]
13 May 2018, 23:52
Yep the answer is b as the triangle is equilateral



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Re: Equilater trinagle PQR is formed by joining [#permalink]
15 May 2018, 22:16
Carcass wrote: Sorry for the inconvenience. fixed.
regards This is yet to be fixed as the answer placed is B,D. Which exactly is it?



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Re: Equilater trinagle PQR is formed by joining [#permalink]
17 May 2018, 00:59
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Emike56 wrote: Carcass wrote: Sorry for the inconvenience. fixed.
regards This is yet to be fixed as the answer placed is B,D. Which exactly is it? The correct answer is B. Here's another explanation why. Let's pretend that the radius (r) = 5. Since the triangle is an equilateral triangle, that means each side of the triangle is 10, or 2 * radius of each circle. Quantity A = Perimeter of Triangle PQR = 30. Quantity B = Circumference of Circle with Center Q = 2 * pi * 5. = 10 * 3.14 = 31.4. Quantity B is greater.
The correct answer is B.



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Re: Equilater trinagle PQR is formed by joining [#permalink]
19 Jan 2019, 15:27
Ans B



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Re: Equilater trinagle PQR is formed by joining [#permalink]
09 Feb 2019, 07:49
Agree, the answer is B if the circles are identical but there is nowhere mentioned in the question that the circles have the same radius. IMO answer should've been D.
Thanks



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Re: Equilater trinagle PQR is formed by joining [#permalink]
09 Feb 2019, 11:14
The assumption is wrong: the stem says that PQR is an equilateral triangle, which means all sides are equal in length. So, if one side is 10 (for instance) the other two are 10 as well. If one side is 10, half of it is 5, which is the radius of all 3 circles. Is the radius is equal, the 3 areas are equal as well. Hope now is clear. Regards
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Re: Equilater trinagle PQR is formed by joining [#permalink]
31 Aug 2020, 09:05
How do you know all Circles are equal? Posted from my mobile device



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Re: Equilater trinagle PQR is formed by joining [#permalink]
31 Aug 2020, 09:46
Because the equilateral triangle has 3 side equal in lenght The same side, added up. is the two radii of a circle. Therefore the circles must be equal
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Re: Equilater trinagle PQR is formed by joining
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31 Aug 2020, 09:46





