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Each of the even-numbered terms in a certain sequence is for

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GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4710
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Kudos [?]: 1613 [0], given: 375

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Each of the even-numbered terms in a certain sequence is for [#permalink] New post 27 Mar 2018, 16:07
Expert's post
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Question Stats:

80% (01:56) correct 20% (01:53) wrong based on 5 sessions
Each of the even-numbered terms in a certain sequence is formed by multiplying the preceding term by –1. Each of the odd-numbered terms in the sequence is formed by adding 3 to the preceding term. If the first term in the sequence is 3, then what is the 168th term?

A. –3
B. –1
C. 0
D. 1
E. 3

Drill 1
Question: 5
Page: 546-547
[Reveal] Spoiler: OA

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Sandy
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GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4710
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 91

Kudos [?]: 1613 [0], given: 375

CAT Tests
Re: Each of the even-numbered terms in a certain sequence is for [#permalink] New post 28 Mar 2018, 13:31
Expert's post
Explanation

Write out sequences until you see the pattern.

The second term in the sequence is 3(–1) = –3.

Adding 3 gives you the third term, 0. Multiplying by –1 gives you the fourth term, also 0.

Adding 3 gives you 3, the fifth term. So the sequence repeats every four terms: 3, –3, 0, 0, 3, –3, 0, 0, and so forth.

Dividing 168 by 4 gives you a remainder of zero, and the fourth, eighth, twelfth, and every other nth term where n is a multiple of 4 (including the 168th term) will all
be the same value, 0. The answer is choice (C).
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Sandy
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Re: Each of the even-numbered terms in a certain sequence is for   [#permalink] 28 Mar 2018, 13:31
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Each of the even-numbered terms in a certain sequence is for

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