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# Each dimension of the rectangular solid pictured is an integ

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Each dimension of the rectangular solid pictured is an integ [#permalink]  06 May 2018, 10:14
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Question Stats:

99% (01:37) correct 0% (00:00) wrong based on 7 sessions
Attachment:

cube2.jpg [ 11.23 KiB | Viewed 426 times ]

Each dimension of the rectangular solid pictured is an integer less than 6. Which of the following is the total surface area of the solid?

A. 24

B. 52

C. 60

D. 68

E. 78
[Reveal] Spoiler: OA

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WE: Engineering (Energy and Utilities)
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Re: Each dimension of the rectangular solid pictured is an integ [#permalink]  03 Aug 2018, 21:43
Carcass wrote:
Attachment:
cube2.jpg

Each dimension of the rectangular solid pictured is an integer less than 6. Which of the following is the total surface area of the solid?

A. 24

B. 52

C. 60

D. 68

E. 78

Volume of the rectangular solid = $$length * width * Height$$

or$$24 = Length * 4 * Height$$

or $$Length * Height = 6$$

Since it is given all sides are less than 6 and are integer

so we can take Length = 3 and Height = 2 or vice-versa as it will end up the same result

Now Surface Area of the rectangular solid =$$2 * ( Length * width) + 2 * (Width * Height) + 2 * (Length * Height) = 2 * ( 12 + 8 + 6) = 52$$
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Re: Each dimension of the rectangular solid pictured is an integ   [#permalink] 03 Aug 2018, 21:43
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