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Each dimension of the rectangular solid pictured is an integ

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Each dimension of the rectangular solid pictured is an integ [#permalink] New post 20 Apr 2018, 10:08
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Each dimension of the rectangular solid pictured is an integer less than 6. Which of the following is the total surface area of the solid?


A. 24

B. 52

C. 60

D. 68

E. 78
[Reveal] Spoiler: OA

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Re: Each dimension of the rectangular solid pictured is an integ [#permalink] New post 24 Apr 2018, 03:28
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surface area of a cuboid is given by \(2(lb +lh + bh)\)
volume \(= l*b*h = 24\)
given b = 4 we can simply the volume as \(l*4 *h = 24\)
or, \(l*h = 6\)
therefore the two dimension must be \(2\) and \(3\) it does not matter whether length is \(2\) or height is \(2\)
Also notice that \(6\) and \(1\) may also be the dimension but question mentions that each dimension is less than \(6\)
now surface area \(= 2(8 + 12 + 6) =52\)
option B
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Re: Each dimension of the rectangular solid pictured is an integ   [#permalink] 24 Apr 2018, 03:28
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Each dimension of the rectangular solid pictured is an integ

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