During a certain week, a seal ate 50 percent of the first 80 smelt it came across, and 30 percent of the remaining smelt it came across. If the seal ate 40 percent of the smelt it came across during the entire week, how many smelt did it eat?


A. 24

B. 32

C. 55

D. 64

E. 80
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Let x = total number of smelt a seal came across

So as per statement we can write:

\((0.5 * 80) + 0.3(x - 80) = 0.4x\)

or \(0.1 x = 16\)

or \(x =160\)

Therefore the seal eat 40% of smelt it came across = \(0.4 * 160 = 64\)
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