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Dick takes twice as long as Jane to run any given distance.

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Dick takes twice as long as Jane to run any given distance. [#permalink]  08 Oct 2019, 04:49
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Dick takes twice as long as Jane to run any given distance.
Starting at the same moment, Dick and Jane run towards each other from opposite ends of the schoolyard, a total distance of x, at their respective constant rates until they meet

 Quantity A Quantity B The fraction of the total distance x that is covered by Jane $${\frac{2}{3}}x$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Last edited by Carcass on 08 Oct 2019, 15:08, edited 1 time in total.
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Re: Dick takes twice as long as Jane to run any given distance. [#permalink]  08 Oct 2019, 10:56
any solutions for this?
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Re: Dick takes twice as long as Jane to run any given distance. [#permalink]  08 Oct 2019, 12:02
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pranab01 wrote:
Dick takes twice as long as Jane to run any given distance. Starting at the same moment, Dick and Jane run towards each other from opposite ends of the schoolyard, a total distance of x, at their respective constant rates until they meet

 Quantity A Quantity B The fraction of the total distance x that is covered by Jane $${\frac{2}{3}}x$$

GIVEN: Dick takes twice as long as Jane to run any given distance.
In other words, Jane travels TWICE as fast as Dick does.
So, for every 1 meter that Dick travels, Jane travels 2 meters.

GIVEN: Starting at the same moment, Dick and Jane run towards each other from opposite ends of the schoolyard, a total distance of x, at their respective constant rates until they meet
This is a CLOSING GAP question.
So, for every 1 meter that Dick travels towards Jane, Jane travels 2 meters towards Dick.
In other words, every time the gap closes by 3 units of length, Jane travels 2 units and Dick travels 1 unit.

Since the initial gap is x, we know that the total COMBINED distances traveled by Dick and Jane is x.
This means Dick traveled 1/3 of x, and Jane traveled 2/3 of x

We get:
QUANTITY A: 2/3 of x
QUANTITY B: (2/3)x

Cheers,
Brent
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Re: Dick takes twice as long as Jane to run any given distance. [#permalink]  09 Oct 2019, 09:45
Dick traveled 1/3 of x, and Jane traveled 2/3 of x (As Jane is twice faster then Dick)

QUANTITY A: 2/3 of x
QUANTITY B: (2/3)x

So, C
Re: Dick takes twice as long as Jane to run any given distance.   [#permalink] 09 Oct 2019, 09:45
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