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Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
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d(d2 – 2d + 1) vs d(d2 – 2d) + 1 [#permalink]
Expert's post 00:00

Question Stats: 82% (00:35) correct 17% (00:29) wrong based on 57 sessions
 Quantity A Quantity B $$d(d^2 - 2d + 1)$$ $$d(d^2 - 2d) + 1$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________

Sandy
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VP Joined: 20 Apr 2016
Posts: 1302
WE: Engineering (Energy and Utilities)
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Kudos [?]: 1342 , given: 251

Re: d(d2 – 2d + 1) vs d(d2 – 2d) + 1 [#permalink]
sandy wrote:
 Quantity A Quantity B $$d(d^2 - 2d + 1)$$ $$d(d^2 - 2d) + 1$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Here ;
Statement 1: $$d(d^2 - 2d + 1)$$ =$$d^3 - 2d^2 + d$$

Statement 2 : $$d(d^2 - 2d) + 1$$ = $$d^3 - 2d^2 + 1$$

So$$d^3 - 2d^2$$ is common in both the statement and can be neglected.

so we are left with "d" in statement 1 and "1" in statement 2

But we donot have any information about d, so d can be > 1 or d can be < 1

Hence option D.
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Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 175

Kudos [?]: 3036 , given: 394

Re: d(d2 – 2d + 1) vs d(d2 – 2d) + 1 [#permalink]
Expert's post
Explanation

In Quantity A, multiply d by every term in the parentheses:

$$d(d^2 - 2d + 1) = (d \times d^2) - (d \times 2d) + (d \times 1) = d^3 - 2d^2 + d$$

In Quantity B, multiply d by the two terms in the parentheses:
$$d(d^2 - 2d) + 1 = (d \times d^2) - (d \times 2d) + 1 = d^3 - 2d^2 + 1$$

Because $$d^3 - 2d^2$$ is common to both quantities, it can be ignored. The comparison is really between d and 1. Without more information about d, the relationship cannot be determined from the information given.
_________________

Sandy
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Try our free Online GRE Test Re: d(d2 – 2d + 1) vs d(d2 – 2d) + 1   [#permalink] 17 Jul 2018, 12:04
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