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d(d2 – 2d + 1) vs d(d2 – 2d) + 1

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GMAT Club Legend
GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1656 [0], given: 396

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d(d2 – 2d + 1) vs d(d2 – 2d) + 1 [#permalink] New post 23 Jun 2018, 12:13
Expert's post
00:00

Question Stats:

86% (00:26) correct 13% (01:01) wrong based on 22 sessions
Quantity A
Quantity B
\(d(d^2 - 2d + 1)\)
\(d(d^2 - 2d) + 1\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Sandy
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Director
Director
Joined: 20 Apr 2016
Posts: 756
Followers: 6

Kudos [?]: 511 [0], given: 94

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Re: d(d2 – 2d + 1) vs d(d2 – 2d) + 1 [#permalink] New post 28 Jun 2018, 16:45
sandy wrote:
Quantity A
Quantity B
\(d(d^2 - 2d + 1)\)
\(d(d^2 - 2d) + 1\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Here ;
Statement 1: \(d(d^2 - 2d + 1)\) =\(d^3 - 2d^2 + d\)

Statement 2 : \(d(d^2 - 2d) + 1\) = \(d^3 - 2d^2 + 1\)

So\(d^3 - 2d^2\) is common in both the statement and can be neglected.

so we are left with "d" in statement 1 and "1" in statement 2

But we donot have any information about d, so d can be > 1 or d can be < 1

Hence option D.
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GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1656 [0], given: 396

CAT Tests
Re: d(d2 – 2d + 1) vs d(d2 – 2d) + 1 [#permalink] New post 17 Jul 2018, 12:04
Expert's post
Explanation

In Quantity A, multiply d by every term in the parentheses:

\(d(d^2 - 2d + 1) = (d \times d^2) - (d \times 2d) + (d \times 1) = d^3 - 2d^2 + d\)

In Quantity B, multiply d by the two terms in the parentheses:
\(d(d^2 - 2d) + 1 = (d \times d^2) - (d \times 2d) + 1 = d^3 - 2d^2 + 1\)

Because \(d^3 - 2d^2\) is common to both quantities, it can be ignored. The comparison is really between d and 1. Without more information about d, the relationship cannot be determined from the information given.
_________________

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Re: d(d2 – 2d + 1) vs d(d2 – 2d) + 1   [#permalink] 17 Jul 2018, 12:04
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