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Cyclist M leaves point P at 12 noon and travels in a straigh

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Cyclist M leaves point P at 12 noon and travels in a straigh [#permalink] New post 19 Sep 2018, 00:40
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Question Stats:

71% (01:30) correct 28% (01:12) wrong based on 7 sessions
Cyclist M leaves point P at 12 noon and travels in a straight path at a constant velocity of 20 miles per hour. Cyclist N leaves point P at 2 PM, travels the same path at a constant velocity, and overtakes M at 4 PM. What was the average speed of N?

(A) 15
(B) 24
(C) 30
(D) 35
(E) 40
[Reveal] Spoiler: OA
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Re: Cyclist M leaves point P at 12 noon and travels in a straigh [#permalink] New post 19 Sep 2018, 02:51
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There are two cyclists traveling along the same path.
One of them lets say cyclist A has a speed of 20 miles per hr and starts traveling at 12 PM
Another cyclist let us say B has a speed that we do not know and that is what is required by the question.
Cyclist B starts traveling along the same path as A but 2 hrs later than A i.e. at 2PM

Also at 4PM both cyclists travel the same distance from the starting point P.

Let us find out how much can cyclist A travel in 4 hrs, that would be \(20*4 = 80\) miles
Since cyclist B started at 2PM and reached the exact distance as cyclist A at 4PM. Cyclist B traveled for 2 hrs only.
Therefore if Cyclist B speed was x miles per hr then 2x = 80
or, \(x = 40\) which is the speed of cyclist B
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This is my response to the question and may be incorrect. Feel free to rectify any mistakes

Intern
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Re: Cyclist M leaves point P at 12 noon and travels in a straigh [#permalink] New post 19 Sep 2018, 09:03
amorphous wrote:
There are two cyclists traveling along the same path.
One of them lets say cyclist A has a speed of 20 miles per hr and starts traveling at 12 PM
Another cyclist let us say B has a speed that we do not know and that is what is required by the question.
Cyclist B starts traveling along the same path as A but 2 hrs later than A i.e. at 2PM

Also at 4PM both cyclists travel the same distance from the starting point P.

Let us find out how much can cyclist A travel in 4 hrs, that would be \(20*4 = 80\) miles
Since cyclist B started at 2PM and reached the exact distance as cyclist A at 4PM. Cyclist B traveled for 2 hrs only.
Therefore if Cyclist B speed was x miles per hr then 2x = 80
or, \(x = 40\) which is the speed of cyclist B


Thank you very much! Can you provide some materials on this very topic or reference me to some for more practice? I am weak in work/rate problems.
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Re: Cyclist M leaves point P at 12 noon and travels in a straigh [#permalink] New post 20 Sep 2018, 04:52
Expert's post
Just click on the tag above the question: work/rate problem. You do have all these questions with this tag

https://greprepclub.com/forum/search.ph ... tag_id=356

Regards
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Re: Cyclist M leaves point P at 12 noon and travels in a straigh   [#permalink] 20 Sep 2018, 04:52
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