ExplanationNote that Quantity B, \(\frac{(1 + x)}{x^2}\) can be expressed as \(\frac{1}{x^2}+\frac{x}{x^2}\), which can be simplified to \(\frac{1}{x^2}+\frac{1}{x}\).

Note that Quantity A is \(\frac{1}{x}\), and for all nonzero values of \(x\), \(\frac{1}{x^2} >0\). It follows that \(\frac{1}{x^2}+\frac{1}{x} > \frac{1}{x}\); that is, Quantity B is greater than Quantity A. Thus the correct answer is

Choice B.

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Sandy

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