jen6 wrote:

In one of the steps in Brent's solution, I didn't understand how the below Quantity B came to be. Can that be explained to me? Thanks.

Factor out 10^(1/3) in quantity B to get:

Quantity A: [10^(1/3)][8^(1/3)]

Quantity B: [10^(1/3)][27^(1/3) - 1]

In the step before that, we have: Quantity B: [27^(1/3)][

10^(1/3)] -

10^(1/3)This similar to the expression x

y -

yWith this expression, we can factor out the

y to get: x

y -

y =

y(x - 1)

Likewise, in the original expression, we can factor out

10^(1/3) to get: [27^(1/3)][

10^(1/3)] -

10^(1/3) = [

10^(1/3)][27^(1/3) - 1]

Does that help?

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

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