Break this into 2 cases

Case1: No inexperienced engineers

total no of engg available= 6

no to be selected = 3

No of ways= 6C3= 20

Case2: One in-experienced engg

no of ways selecting one in-exp engg =2

no of ways of selecting other 2 guys = 6C2 = 30

So total no of ways = 2 *15 = 30

So total no of combinations = case 1 + case 2 = 20+30 =50PS Share the OA and source

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Sandy

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