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combination question

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Intern
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combination question [#permalink] New post 19 Nov 2016, 12:24
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ben needs to form a committee of 3 from a group of 8 engineers to study design improvements for a product. if two of the engineers are too inexperienced to serve together on the committee , how many different committees can ben form?
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Re: combination question [#permalink] New post 19 Nov 2016, 12:58
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Break this into 2 cases

Case1: No inexperienced engineers

total no of engg available= 6
no to be selected = 3

No of ways= 6C3= 20

Case2: One in-experienced engg

no of ways selecting one in-exp engg =2
no of ways of selecting other 2 guys = 6C2 = 30

So total no of ways = 2 *15 = 30


So total no of combinations = case 1 + case 2 = 20+30 =50


PS Share the OA and source
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Re: combination question [#permalink] New post 19 Nov 2016, 13:48
sandy wrote:
Break this into 2 cases

Case1: No inexperienced engineers

total no of engg available= 6
no to be selected = 3

No of ways= 6C3= 120

Case2: One in-experienced engg

no of ways selecting one in-exp engg =2
no of ways of selecting other 2 guys = 6C2 = 30

So total no of ways = 2 *30 = 60


So total no of combinations = case 1 + case 2 = 120+60 =180


PS Share the OA and source



sandy , thanks for the reply . but the answer is 50 as per the book. which one is correct 50 or 180 .
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Re: combination question [#permalink] New post 19 Nov 2016, 15:07
Expert's post
Which book?

Please share the question details as this is a forum for students. This enables other students use the material we discuss here.

Please add tags to the question as per rules of the forum.

Regards




PS: I have corrected the answer. it is indeed 50.
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Re: combination question [#permalink] New post 20 Nov 2016, 01:55
sandy wrote:
Which book?

Please share the question details as this is a forum for students. This enables other students use the material we discuss here.

Please add tags to the question as per rules of the forum.

Regards




PS: I have corrected the answer. it is indeed 50.



question details? i gave every thing that is present about the question , question and the answer. its a private institute gre test prep book where questions and their answers are shared nothing else.

thank you
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Re: combination question [#permalink] New post 04 Feb 2017, 08:59
Answer 50 is correct.Consider this case:
When no. of combinations when both inexperienced are not together=Total no. of combinations-no. of combinations when both inexperienced are together=8C3-6C1(as two members are inexperienced engineers and we have to select only one member from all experienced engineers(6))=56-6=50.
Hope it helps.
Re: combination question   [#permalink] 04 Feb 2017, 08:59
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