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Claudette traveled the first of a 60-mile trip at 20 miles p

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GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Claudette traveled the first of a 60-mile trip at 20 miles p [#permalink] New post 15 Jul 2018, 02:43
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Question Stats:

66% (00:33) correct 33% (01:56) wrong based on 6 sessions
Claudette traveled the first \(\frac{2}{3}\) of a 60-mile trip at 20 miles per hour (mph) and the remainder of the trip at 30 mph. How many minutes later would she have arrived if she had completed the entire trip at 20 mph?


?? minutes

[Reveal] Spoiler: OA
20

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Sandy
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GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1650 [0], given: 396

CAT Tests
Re: Claudette traveled the first of a 60-mile trip at 20 miles p [#permalink] New post 15 Jul 2018, 02:52
Expert's post
Explanation


First, figure out how long it took Claudette to travel 60 miles under the actual conditions.

The first leg of the trip was \(\frac{2}{3}\)of 60 miles, or 40 miles.

To travel 40 miles at a rate of 20 miles per hour, Claudette spent \(\frac{40}{20}= 2\)hours = 120 minutes.

The second leg of the trip was the remaining 60 – 40 = 20 miles. To travel that distance at a rate of 30 miles per hour, Claudette spent \(\frac{20}{30}= \frac{2}{3}\)hours= 40 minutes.


In total, Claudette traveled for 120 + 40 = 160 minutes. Now consider the hypothetical trip. If Claudette had traveled the whole distance of 60 miles at 20
miles per hour, the trip would have taken \(\frac{180}{20}= 3\)hours= 180 minutes.

Finally, compare the two trips. The real trip took 160 minutes, so the hypothetical trip would have taken 180 – 160 = 20 minutes longer.
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Sandy
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Re: Claudette traveled the first of a 60-mile trip at 20 miles p   [#permalink] 15 Jul 2018, 02:52
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Claudette traveled the first of a 60-mile trip at 20 miles p

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