It is currently 17 Jun 2019, 21:52
My Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Chris gave Jane x cards. He gave Betty one card more than he

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Founder
Founder
User avatar
Joined: 18 Apr 2015
Posts: 6885
Followers: 114

Kudos [?]: 1338 [0], given: 6306

CAT Tests
Chris gave Jane x cards. He gave Betty one card more than he [#permalink] New post 12 Jun 2018, 04:22
Expert's post
00:00

Question Stats:

100% (01:23) correct 0% (00:00) wrong based on 4 sessions
Chris gave Jane x cards. He gave Betty one card more than he gave Jane and he gave Paul two cards fewer than he gave Betty. In terms of x, how many cards did Chris give Betty, Jane, and Paul altogether?

(A) \(3x + 1\)

(B) \(3x\)

(C) \(3x - 1\)

(D) \(x - 1\)

(E) \(\frac{x}{3}\)
[Reveal] Spoiler: OA

_________________

Get the 2 FREE GREPrepclub Tests

1 KUDOS received
GRE Forum Moderator
Joined: 29 May 2018
Posts: 125
Followers: 0

Kudos [?]: 86 [1] , given: 4

Re: Chris gave Jane x cards. He gave Betty one card more than he [#permalink] New post 13 Jun 2018, 22:53
1
This post received
KUDOS
Carcass wrote:
Chris gave Jane x cards. He gave Betty one card more than he gave Jane and he gave Paul two cards fewer than he gave Betty. In terms of x, how many cards did Chris give Betty, Jane, and Paul altogether?

(A) \(3x + 1\)

(B) \(3x\)

(C) \(3x - 1\)

(D) \(x - 1\)

(E) \(\frac{x}{3}\)


I solved in different way. Let me know whether this is correct.

Let x be 9 , looking at options, decided to go for this.

options will be:
a.10
b.27
c.26
d.8
e.3

When we have given info that Chris gave x cards to Jane, i.e. 9 cards as per our case then we can eliminate a,d and e options.

Take option b as it bigger number than c.

Chris has 27 cards = 9(Jane) + one more than to Betty than Jane(10) + two cards fewer than Paul than Betty (8).

27 = 27.

Hence B.
Re: Chris gave Jane x cards. He gave Betty one card more than he   [#permalink] 13 Jun 2018, 22:53
Display posts from previous: Sort by

Chris gave Jane x cards. He gave Betty one card more than he

  Question banks Downloads My Bookmarks Reviews Important topics  


GRE Prep Club Forum Home| About| Terms and Conditions and Privacy Policy| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.