I solved in different way. Let me know whether this is correct.

Let x be 9 , looking at options, decided to go for this.

options will be:
a.10
b.27
c.26
d.8
e.3

When we have given info that Chris gave x cards to Jane, i.e. 9 cards as per our case then we can eliminate a,d and e options.

Take option b as it bigger number than c.

Chris has 27 cards = 9(Jane) + one more than to Betty than Jane(10) + two cards fewer than Paul than Betty (8).

27 = 27.

Hence B.