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Child A ate 3/5 of a kilogram of chocolate and Child B ate 3 [#permalink]
19 May 2018, 12:20

Expert's post

00:00

Question Stats:

70% (00:35) correct
30% (00:55) wrong based on 30 sessions

Child A ate \(\frac{3}{5}\) of a kilogram of chocolate and Child B ate 300 grams of chocolate. (1kilogram = 1000 grams)

Quantity A

Quantity B

The weight, in grams, of the chocolate that Child A ate

Twice the weight, in grams, of the chocolate that Child B ate

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

Re: Child A ate 3/5 of a kilogram of chocolate and Child B ate 3 [#permalink]
06 Sep 2018, 12:32

Arc29 wrote:

A= (3/5)*1000=600 B=2*300 =600 hence answer C

instead of (3/5)*1000=600 my friend what you can do is just multiply 2 on both numerator and denominator so its becomes easier to estimate the percentage hence easy to determine the weight. it would be 6/10 which is 60% so 600 grams. just make denominator either 10, 100 or as close to 100 as possible so you can take an approximation

greprepclubot

Re: Child A ate 3/5 of a kilogram of chocolate and Child B ate 3
[#permalink]
06 Sep 2018, 12:32