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Chelsea has a bookshelf consisting of ten classics: four Rus

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Chelsea has a bookshelf consisting of ten classics: four Rus [#permalink] New post 04 Oct 2017, 20:34
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Chelsea has a bookshelf consisting of ten classics: four Russian novels, three British novels, two French novels, and a German novel. If she wants to make sure that the novels are always grouped according to country, how many ways can she arrange the novels?

(A) 24

(B) 24^2

(C) 288

(D) (24)(288)

(E) 144^2

Kudos for correct solution.
[Reveal] Spoiler: OA
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Re: Chelsea has a bookshelf consisting of ten classics: four Rus [#permalink] New post 04 Oct 2017, 22:29
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Bunuel wrote:
Chelsea has a bookshelf consisting of ten classics: four Russian novels, three British novels, two French novels, and a German novel. If she wants to make sure that the novels are always grouped according to country, how many ways can she arrange the novels?

(A) 24

(B) 24^2

(C) 288

(D) (24)(288)

(E) 144^2

Kudos for correct solution.


4 Russian novels can be arranged in 4! ways =24 ways

3 British novels can be arranged in 3! ways = 6 ways

2 French novels can be arranged in 2! ways =2 ways

1 German Novel can be arranged in 1! way = 1 way

Therefore the novels can be arranged within the group = (24 x 6 x 2) = 288 ways

Now this group (4 different novels) can be arranged in = 4! ways = 24 ways

Therefore the total no. of ways= 24 * 288 ways
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Re: Chelsea has a bookshelf consisting of ten classics: four Rus   [#permalink] 04 Oct 2017, 22:29
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Chelsea has a bookshelf consisting of ten classics: four Rus

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