Carcass wrote:

Carla has \(\frac{1}{4}\) more sweaters than cardigans, and \(\frac{2}{5}\) fewer cardigans than turtle necks. If she has at least one of each item, what is the minimum total number of turtlenecks plus sweaters that Carla could have?

Given

S = \((\frac{1}{4} +1)*C\)

= \((\frac{5}{4})*C\)

and C = \((1-\frac{2}{5} )*T\)

= \((\frac{3}{5})*T\)

or T = \((\frac{5}{3})*C\)

Now

Let C = 12 (since it is a factor of 4 and 3. It should be the minimum value)

therefore S= \((\frac{5}{4})*12\)

or S = 15

and T =\((\frac{5}{3})*12\)

or T = 20

Therefore the sweater and turtle neck = 15+20 =35

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