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c < –1

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c < –1 [#permalink] New post 19 Jul 2019, 09:47
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Question Stats:

76% (00:30) correct 23% (00:34) wrong based on 55 sessions
\(c < –1\)

Quantity A
Quantity B
\(6c-3\)
\(3c-5\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
[Reveal] Spoiler: OA

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Re: c < –1 [#permalink] New post 14 Jan 2020, 06:46
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Re: c < –1 [#permalink] New post 14 Jan 2020, 23:20
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Add 3 on both quantities.
Qa: 6c............................Qb=3c-2

Subtract 3C from both quantities,
Qa: 3c............................Qb=-2

Even if c=-1, 3c=-3. Since c<-1, 3c must be less than -3.
So, Quantity b is greater.
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Re: c < –1 [#permalink] New post 15 Jan 2020, 03:07
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Addition and subtraction in inequality in any case is accepted:
(A) 6c-3 ? (B)3c-5 just solve it like algebraic expressions.
3C ? -2 Simple addition and subtraction on both sides.
C ? -2/3 Dividing by 3(being positive no.) on both sides is accepted.
Since c<–1, (B) is the answer.
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Re: c < –1 [#permalink] New post 15 Jan 2020, 16:12
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Carcass wrote:
\(c < –1\)

Quantity A
Quantity B
\(6c-3\)
\(3c-5\)



We can solve this question using matching operations

Given:
Quantity A: \(6c-3\)
Quantity B: \(3c-5\)

Add \(3\) to both quantities to get:
Quantity A: \(6c\)
Quantity B: \(3c-2\)

Subtract \(3c\) from both quantities to get:
Quantity A: \(3c\)
Quantity B: \(-2\)

Divide both quantities by \(3\) to get:
Quantity A: \(c\)
Quantity B: \(-\frac{2}{3}\)

Since \(-1 < -\frac{2}{3}\), and since it's given that \(c < –1\), we can combine both inequalities to get: \(c < -1 < -\frac{2}{3}\)
This means \(c < -\frac{2}{3}\), so Quantity B is greater.

Answer: B


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Re: c < –1   [#permalink] 15 Jan 2020, 16:12
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